converting json branched array to php object

Question

In below code, I want to display get_data using echo but not able to decode/display branched array. So, My question is how to convert branched array to PHP object.

Json Response :

{"status":1,"msg":"fetched Succesfully","user_data":{"d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba":{"name":"PRATYUSH","user_year":"2013","get_data":"d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba","is_active":1,"data_no":"ghjgjj2XXXXXXoioo7","user_bin":"77","is_exp":"N"}}}

PHP CODE :(after using curl)

$response = json_decode($o,true);
$status=$response["status"];
$msg=$response["msg"];
$user_data=$response["user_data"][0]["get_data"];

RESULT:

echo $status;//(working)
echo "<br>";
echo $msg;//(working)
echo "<br>";
echo $user_data;//(Not working)

echo User_data is not working.

I mean to ask, did you get your result in such a way?? > Array( ["status"] => '1', ["msg"] => "fetched Succesfully", ["user_data"] => Array( ["d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba"] => Array( ["name"] => "PRATYUSH", ["user_year"] => "2013", ["get_data"] => "d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba", ["is_active"] => 1, ["data_no"] => "ghjgjj2XXXXXXoioo7", ["user_bin"] => "77", ["is_exp"] => "N" ) ) ) — Keyur Mistry
– Keyur Mistry, Commented Jan 21, 2016 at 5:53
@abhishek What to do when there is more than one get_data in at json response? Like below {"status":1,"msg":"fetched Succesfully","user_data":{"d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba":{"name":"PRATYUSH","user_year":"2013","get_data":"d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba","is_active":1,"data_no":"ghjgjj2XXXXXXoioo7","user_bin":"77","is_exp":"N"},"ty6c2d21af80002a3dd6ffc76f62bb9f89b6e0ba":{"name":"PghfghH","user_year":"2015","get_data":"ty6c2d21af80002a3dd6ffc76f62bb9f89b6e0ba","is_active":1,"data_no":"ghjgjj2XXXXXXoioo7","user_bin":"77","is_exp":"N"}}} — user3588059
– user3588059, Commented Jan 21, 2016 at 7:10

A J · Accepted Answer · 2016-01-21 06:05:02Z

1

So you want to get value of get_data. If d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba is not known, try this way.

$user_data_arr=$response["user_data"]; 
foreach($user_data_arr AS $user_data_obj)
{
    echo $user_data_obj['get_data'];// here is your desired value
}

Using foreach loop, you do not have to find index and you can get values easily.

Full Code

 $response = json_decode($o,true);
 $status=$response["status"];
 $msg=$response["msg"];
 $user_data="";
 $user_data_arr=$response["user_data"]; 
  foreach($user_data_arr AS $user_data_obj)
  {
    $user_data = $user_data_obj['get_data'];// here is your desired value
  }
 echo $status;
 echo "<br>";
 echo $msg;
 echo "<br>";
 echo $user_data;//will work

edited Jan 21, 2016 at 6:05

answered Jan 21, 2016 at 5:57

A J

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Comments

makallio85 · Accepted Answer · 2016-01-21 05:37:40Z

0

Change

$user_data=$response["user_data"][0]["get_data"];

to this

$user_data=$response["user_data"]["d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba"]["get_data"];

answered Jan 21, 2016 at 5:37

makallio85

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1 Comment

user3588059 Over a year ago

"d91c2d21af80002a3dd6ffc76f62bb9f89b6e0ba" comes in json response part, I can't use this value.

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