Remove duplicates pair in an array and also in reverse order PHP Laravel

Question

I have an array

array:2 [▼
      0 => array:2 [▼
        0 => 159
        1 => 158
      ]
      1 => array:2 [▼
        0 => 159
        1 => 158
      ]
      2 => array:2 [▼
        0 => 158
        1 => 159
      ]
    ]

I want to delete the duplicate ones and the duplicate in reverse order. For example index 0 and index 1 has the same values 159 and 158 also same in order like 0 => 159 and 1 => 158 . I want to delete either index 1 or 0. Since it is same. And if you noticed index 2. it has the same value only difference is the order 0 => 158 and 1 => 159 I also want to delete this since it is the same pair values. How can I do that if that array is $remove_arr

So since I will delete index 2 and either index 0 or 1 there should only be one index left.

Bogdan · Accepted Answer · 2016-01-14 14:34:58Z

2

Here's a shorter solution:

$data = [[158, 159], [158, 159], [159, 158]];

$unique = array_unique(array_map(function ($item) {
    sort($item); return $item;
}, $data), SORT_REGULAR);

dump($unique); // This will output [[158, 159]]

This solution sorts the contents of the level 2 arrays. So after sorting, the last value will also become [158, 159] so it can be correctly evaluated by array_unique as a duplicate.

answered Jan 14, 2016 at 14:34

Bogdan

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1 Comment

splash58 Over a year ago

I did not have a step up this variant :). +1

splash58 · Accepted Answer · 2016-01-14 10:57:43Z

1

count(array_intersect()) gets the amount of the same items in the array. When it equal the array lenght, remove one of them

$remove_arr = [
[158, 159],
[158, 159],
[159, 158]
];

for($i = count($remove_arr)-1; $i >= 0 ; $i--) {
   $j = $i-1; 
   while ($j >= 0) { 
      if (count(array_intersect($remove_arr[$i],$remove_arr[$j])) == count($remove_arr[$i]))
           { unset($remove_arr[$i]); break; }
       else $j--;
   }
}

print_r($remove_arr);

answered Jan 14, 2016 at 10:57

splash58

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1 Comment

jackhammer013 Over a year ago

Thanks. Will look into it :)

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