Storing array in hidden input, and using ajax to print out

Question

I'm trying to store an array in the value of an element, and then use ajax to print the array, but when I tried to print the array, using print_r(), instead of printing the array, it printed the word array. What am I doing wrong?

<?php

$array[0] = 0;
$array[1] = 1;
$array[2] = 2;

echo "<input id = 'array' type = 'hidden' value = '$array'>";
//more codes

?>

In JavaScript:

var array = $("#"+array).val();
//more codes
data: { array: array },

On Second Page

array = $_POST['array'];
print_r(array);

Result

array

Expected Result

0
1
2

var array = $("#"+array).val(); ==> var array = $("#array").val(); — Tushar
– Tushar, Commented Jan 12, 2016 at 3:08
you can use json_encode while outputting the value on the input field and on next page before using the value use json_decode. You can also use serialize and unserialize to achieve the same effect — Saqib Amin
– Saqib Amin, Commented Jan 12, 2016 at 3:13
Why are you doing this anyway? PHP session variables may be a better way if you're just passing data between pages. — Matt
– Matt, Commented Jan 12, 2016 at 3:26

Firat Akandere · Accepted Answer · 2016-01-12 03:10:20Z

2

Convert your array to json before using it on JavaScript

echo "<input id = 'array' type = 'hidden' value = '" . json_encode($array) . "'>";

And decode it on the second page:

$array = json_decode($_POST['array']);
print_r(array);

answered Jan 12, 2016 at 3:10

Firat Akandere

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Bin Zhou · Accepted Answer · 2016-01-12 03:25:30Z

0

javascript and php have different syntax to use with array.

you should use

echo "<input id = 'array' type = 'hidden' value = '". implode(',', $array) ."'>";

...

On Second Page

$array = $_POST['array']; array = explode(',', $array); print_r(array);

answered Jan 12, 2016 at 3:25

Bin Zhou

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