How to compare an input string using if statement

Question

I am giving an input, that gets stored in the variable "inp". When I compare it in the if condition shown below, I am not getting the right output. The for loop is executed, but no output is shown. When I replace the variable by string "bin_A", I am getting the right output.

Here is the snippet of my code:

def main():
    with open("apc.json") as data_file:
      data = json.load(data_file)

    inp = raw_input("enter name") 
    print "read the input", str(inp)   
    for i in range(0,12):

      if data["work_order"][i]["bin"] == inp :  #have tried repr(inp)
          print data["work_order"][i]["bin"]
          print "gotcha", i
          print data["work_order"][i]["item"]

if __name__ == '__main__':
    main()

Note: Output of print data["work_order"][i]["bin"] is Bin_A. So, when I try to give my input as Bin_A, nothing happens

what is the type of data data["work_order"][i]["bin"]?? if is not str, then they never will be equals., Also try str(data[...]) given that the print is as you say... — Copperfield
– Copperfield, Commented Jan 9, 2016 at 23:48

Cory Kramer · Accepted Answer · 2016-01-09 22:46:56Z

2

Considering data was set from

data = json.load(data_file)

Then you probably need to convert the variable i from an int to a str

if data["work_order"][str(i)]["bin"] == inp

Or since you seem to use i multiple times, you could directly say

for i in map(str, range(0,12)):

answered Jan 9, 2016 at 22:46

Cory Kramer

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2 Comments

Username Over a year ago

conversion [str(i)] doesn't seem to work as well. But, could you please explain the reason for conversion ?

user1544337 Over a year ago

Perhaps str(data["work_order"][i]["bin"]), if otherwise an object is returned?

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