handling strings in python?

Question

s5=0
for phrase in root.findall('./PHRASE'):
    ens = {en.get('x'): en.text for en in phrase.findall('en')}
    if 'ORG' in ens and 'PERS' in ens:
      if (ens["ORG"] =="XYZ Corp" and ens["PERS"]=="John"):
          print("ORG is: {}, PERS is: {} /".format(ens["ORG"], ens["PERS"]))
          y="".join(phrase.itertext())   #print whats in between
          print(y)
          s5 = s5+1
print("occurrence of fifth seed : ",s5)

Here in each iteration, Y is printed, Y is the text in the XML document as long as I have 2 "en" tags, one ORG & 1 PERS.

So the output is:

John cofounder of XYZ Corp.
John works in XYZ Corp.
John named his company XYZ Corp.

I have been trying to save each sentence on its own so I can use it later. For example I want to use the second sentence "John works in XYZ Corp" I don't know how to do that, I tried using the variable Y as 2d array but I failed.

What the problem to create a list and append results in for loop? l = [] and then l.append(y) before print statement... — Anton Protopopov
– Anton Protopopov, Commented Jan 5, 2016 at 23:22

Stidgeon · Accepted Answer · 2016-01-05 23:25:41Z

1

As commented above:

    sentences = []
    y="".join(phrase.itertext())   #print whats in between
    print(y)
    sentences.append(y)

Then get the sentences back by indexing in to the 'sentences' list:

    print sentence[0] # first sentence
    print sentence[1] # second sentence, etc.

answered Jan 5, 2016 at 23:25

Stidgeon

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