PHP variable within an HTML query string

Question

I have an ASP site, and I am tracking traffic. The header includes the line:

<img alt="" src="http://xxxxxxxxx.co.uk/pixel.asp?visitorreferringurl=<% =Request.ServerVariables("HTTP_REFERER") %>" width="1" height="1" />

The target ASP page tracks the original referrer (from the passed query string) and the page the user is visiting (on the pixel.asp page this is actually the referer).

All is good.

I also have a Wordpress site (hence PHP) and I am trying to do the same. I can get pixel.asp to record but can't pass the referrer. I have tried..

<img alt="" src="http://xxxxxxx.co.uk/pixel.asp?visitorreferringurl<?php $_SERVER['HTTP_REFERER']; ?>" width="1" height="1" />

I also tried to declare the $_SERVER['HTTP_REFERER'] as a variable and then use that, but still no result.

Any suggestion please?

Missing the "echo" in your <?php $_SERVER.... ?>

VikingBlooded
– VikingBlooded

2015-12-14 14:27:32 +00:00
Commented Dec 14, 2015 at 14:27 — VikingBlooded
– VikingBlooded, Commented Dec 14, 2015 at 14:27

Jørgen R · Accepted Answer · 2015-12-14 14:01:42Z

2

You forgot to output the information in your variable.

Try this:

<?php echo $_SERVER['HTTP_REFERER']; ?>

Additional information:

You don't need to close the img tag with a trailing slash, so <img src="img"> is perfectly valid. Also, setting the alt attribute for the sake of setting it isn't useful, so either have some information there or drop it altogether.

edited Dec 14, 2015 at 14:01

answered Dec 14, 2015 at 13:54

Jørgen R

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Comments

Daniele D · Accepted Answer · 2015-12-14 15:27:35Z

0

You need to use "echo" to output the variable. See: http://php.net/manual/en/function.echo.php

[img alt="" src="http://xxxxxxx.co.uk/pixel.asp?visitorreferringurl=<?php echo $_SERVER['HTTP_REFERER']; ?>" width="1" height="1" /]"

edited Dec 14, 2015 at 15:27

answered Dec 14, 2015 at 13:54

Daniele D

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4 Comments

Daniele D Over a year ago

Didn't realize this. Fixed it. Thank you.

Nick Bridgens Over a year ago

Thank you! Thought I had tried that... but it works perfectly!

Nick Bridgens Over a year ago

but you didn't spot the deliberate error.. the missing equals sign before the php code.

Daniele D Over a year ago

@Nick Bridgens included that for you. Would be great if you choose an accepted answer.

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