Mind has gone blank this afternoon and can't for the life of me figure out the right way to do this:
if(i!="3" && i!="4" && i!="5" && i!="6" && i!="7" && i!="8" && i!="9" && i!="2" && i!="19" && i!="18" && i!="60" && i!="61" && i!="50" && i!="49" && i!="79" && i!="78" && i!="81" && i!="82" && i!="80" && i!="70" && i!="90" && i!="91" && i!="92" && i!="93" && i!="94"){
//do stuff
}
All those numbers need to be in an array, then I can check to see if "i" is not equal to any 1 of them.
var a = [3,4,5,6,7,8,9];
if ( a.indexOf( 2 ) == -1 ) {
// do stuff
}
indexOf returns -1 if the number is not found. It returns something other than -1 if it is found. Change your logic if you want.
Wrap the numbers in quotes if you need strings ( a = ['1','2'] ). I don't know what you're dealing with so I made them numbers.
IE and other obscure/older browsers will need the indexOf method:
if (!Array.prototype.indexOf)
{
Array.prototype.indexOf = function(elt /*, from*/)
{
var len = this.length >>> 0;
var from = Number(arguments[1]) || 0;
from = (from < 0)
? Math.ceil(from)
: Math.floor(from);
if (from < 0)
from += len;
for (; from < len; from++)
{
if (from in this &&
this[from] === elt)
return from;
}
return -1;
};
}
My mind made this solution:
function not(dat, arr) { //"not" function
for(var i=0;i<arr.length;i++) {
if(arr[i] == dat){return false;}
}
return true;
}
var check = [2,3,4,5,6,7,8,9,18,19,49,50,60,61,70,78,79,80,81,82,90,91,92,93,94]; //numbers
if(not(i, check)) {
//do stuff
}
indexOf is that it's already built into most modern browsers.This solution is cross-browser:
var valid = true;
var cantbe = [3, 4, 5]; // Fill in all your values
for (var j in cantbe)
if (typeof cantbe[j] === "number" && i == cantbe[j]){
valid = false;
break;
}
valid will be true if i isn't a 'bad' value, false otherwise.
for...in on arrays.
typeof cantbe[j] === "number".
for-in is meant to enumerate object properties, to iterate over array objects, a sequential loop is always the best, more details here.