Python Open File Button

Question

I am having trouble, trying to get my open button to open a text file. I want it to open the text file into the not pad, when I click the open button. If some one could help me or tell me what I am doing wrong, I would appreciate it.

def _open(self):
        open("../Address.txt","r").close()
        with open("../Address.txt", "a") as file:
            self._outputArea.insert("1.0", file.read)
            file.read()

101 · Accepted Answer · 2015-12-07 01:56:46Z

1

Why open and close the file first? Just use the with line.
Don't use file as a variable name, it's also a type.
You're not calling read.
'a' is a flag for appending a file, use 'r' (for read) instead.

Try something like:

def _open(self):
    with open("../Address.txt", "r") as the_file:
        self._outputArea.insert("1.0", the_file.read())

answered Dec 7, 2015 at 1:56

101

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6 Comments

Michael Schultz Over a year ago

It gives me this error when I click the open button File "E:\Mike's CPT-135 python class\Project2\src\GroupProject.py", line 226, in _open file.read() io.UnsupportedOperation: not readable

101 Over a year ago

Does the file exist yet?

Michael Schultz Over a year ago

it's not opening it to the text field aka not pad

101 Over a year ago

Strange, I can't see why you'd get that error with the above code.

Michael Schultz Over a year ago

it's creating a text file, but I want it to open up in a note pad I have with in my program

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