I'd like to know all distinct extensions of files tracked by git in a given repo, in order to create appropriate .gitattributes file.
Example output expected:
bat
gitignore
gradle
html
jar
java
js
json
md
png
properties
py
svg
webp
xml
yml
What command can I use for that?
git ls-tree -r HEAD --name-only | perl -ne 'print $1 if m/\.([^.\/]+)$/' | sort -u
When you declare it as an alias, you have to escape $1:
alias gitFileExtensions="git ls-tree -r HEAD --name-only | perl -ne 'print \$1 if m/\.([^.\/]+)$/' | sort -u"
This is better than naive find, because:
.git directory which contains usually hundreds/thousands of files and hence slows down the search(inspired by How can I find all of the distinct file extensions in a folder hierarchy?)
&& !$a{$1}++ (with single quotes around the whole command) to only print the first occurrence of each result.
SCALAR(0xa031e3c)SCALAR(0xa031e3c).... I have to remove the escape before $1 for it to work back. But then when I declare an alias, I have to add the escape back. Updated.$ needs escaping from the shell inside double quotes. Better to just use a function in my opinion.!$a{$1}++ I tested on a huge git repo (Chrome's blink) and the speed difference is negligible in practice (0.8s vs 1.0s on my machine). I think I'll leave sort for readability :)If you have access to PowerShell, here is a nice one-liner which also gives you the count of how many files exist of each type:
$ext = @{}; git ls-tree -r HEAD --name-only | Get-Item | %{ $ext[$_.Extension]++ }; $ext
