Pass arguments from array in php to constructor [duplicate]

Question

Normally, if I want to pass arguments from $myarray to $somefunction I can do this in php using

call_user_func_array($somefunction, $myarray);

However this does not work when the function one wishes to call is the constructor for an object. For fairly obvious reasons it does not work to do:

$myobj = new call_user_func_array($classname, $myarray);

is there something fairly elegant that does work ?

Community · Accepted Answer · 2023-11-17 20:24:09Z

67

You can use the Reflection API:

ReflectionClass::newInstanceArgs — Creates a new class instance from given arguments.

Example:

$reflector = new ReflectionClass('Foo');
$foo = $reflector->newInstanceArgs(array('foo', 'bar'));

edited Nov 17, 2023 at 20:24

CommunityBot

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answered Aug 3, 2010 at 11:16

Gordon

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2 Comments

jhuet Over a year ago

In PHP 5.6 you can also use argument unpacking via the ... or splat operator : php.net/manual/en/…

Shaun Cockerill Over a year ago

Quick and easy! I was already using the Reflection API in my new package loader module, and this gives me a way to account for any number of arguments in future versions.

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