Html.ActionLink and HTML as parameter (ASP.Net MVC 2)

Question

Html.ActionLink("<span class=\"title\">Retry</span><span class=\"arrow\"></span>", "Login", "User")

Hi,

If I execute above code in ASP.Net MVC 2, I get the following output on my screen: Error? http://img27.imageshack.us/img27/2069/screenerror.png

How do I disable the escaping of the code, so my span is within the ActionLink, and not displayed as output?

I know this is expected behavior, to keep it safe, but I want it to interpret the HTML code I pass as a parameter.

Thanks! Yvan

what are you trying to achieve? <a><span></span></a>? I dont think that valid html or xhtml! — Ahmad
– Ahmad, Commented Jul 31, 2010 at 18:22
Ok - so I was smoking my socks with my initial comment, see stackoverflow.com/questions/3379392/… — Ahmad
– Ahmad, Commented Jul 31, 2010 at 19:02
I'm using iWebkit (iwebkit.net) to create native-looking websites for the iPhone. I'm desinging a Mafia-Wars style RPG ;-) — friedkiwi
– friedkiwi, Commented Jul 31, 2010 at 19:25

SLaks · Accepted Answer · 2010-07-31 18:23:11Z

4

The ActionLink helper method can only be used for plain-text links.

You should manually make an <a> tag, like this:

<a href="<%=Url.Action("Login", "User") %>">
    <span class="title">Retry</span><span class="arrow"></span>
</a>

answered Jul 31, 2010 at 18:23

SLaks

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2 Comments

friedkiwi Over a year ago

How should I do that? I know how to make an <a> tag, but which must be the href parameter? I'm quite new to all this MVC-stuff ;)

friedkiwi Over a year ago

Thank you! This helped me out, since I want to deploy on IIS 6, and from the things I read, I need to change some settings, which will render hardcoded paths in the href parameter invalid.

bastijn · Accepted Answer · 2010-10-06 08:05:34Z

0

I think the following also works.

<span class="title"><%= html.actionlink("Retry","Login", "User") %></span><span 
class="arrow"></span>

I mean, <.span>Retry<./span> is just <.span>plaintext<./span> which is the same as the actionlink text? ("." inserted for SO)

answered Oct 6, 2010 at 8:05

bastijn

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