PHP - How to create such array?

Question

The question is simple, I want to create the array below dynamically, but the code I got now only outputs the last row. Is there anybody who knows what is wrong with my dynamically array creation?

$workingArray = [];
$workingArray =
[
    0 =>
    [
        'id' => 1,
        'name' => 'Name1',
    ],
    1 =>
    [
        'id' => 2,
        'name' => 'Name2',
    ]
 ];
echo json_encode($workingArray);


/* My not working array */
$i = 0;
$code = $_POST['code'];
$dynamicArray = [];
foreach ($Optionsclass->get_options() as $key => $value) 
{
    if ($value['id'] == $code) 
    {
        $dynamicArray =
        [
            $i =>
            [
                'id' => $key,
                'name' => $value['options']
            ]
        ];
        $i++;
    }
} 
echo json_encode($dynamicArray);

RiggsFolly · Accepted Answer · 2015-11-07 11:05:52Z

2

You dont need to have the $i stuff that is adding another level to your array that you dont want.

$code = $_POST['code'];
$dynamicArray = [];
foreach ($Optionsclass->get_options() as $key => $value) 
{
    if ($value['id'] == $code) 
    {
        $dynamicArray[] = ['id' => $key, 'name' => $value['options'];
    }
} 
echo json_encode($dynamicArray);

answered Nov 7, 2015 at 11:05

RiggsFolly

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1 Comment

Piet Over a year ago

Awesome, this is working nicely! Great for the very quick answer too.

jconder · Accepted Answer · 2015-11-07 11:08:17Z

2

You are creating a new dynamic array at each iteration:

$dynamicArray =
        [
            $i =>
            [
                'id' => $key,
                'name' => $value['options']
            ]
        ];

Instead, declare $dynamicArray = []; above the foreach, and then use:

array_push($dynamicArray, [ 'id' => $key, 'name' => $value['options']);

inside the array.

answered Nov 7, 2015 at 11:08

jconder

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1 Comment

Piet Over a year ago

Also thanks for the working answer and for the very quick reply!

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