I am trying to query a database for records that have a string field inside an input search string.
Something like this:
User.query.filter(User.name in search_string)
Of course that does not work since it is not a valid SQLAlchemy statement. This seems a simple problem but I really can't find the right column operator.
I tried the in_ operator:
User.query.filter(User.name.in_(search_string)
But that of course is not working. What I need is a is_substring operator.
In SQL it would be
SELECT * FROM user
WHERE 'search string' LIKE CONCAT('%', name, '%')
SQLAlchemy contains(other) produces the clause LIKE '%<other>%'
from sqlalchemy import literal
User.query.filter(literal(search_string).contains(User.name))
from sqlalchemy import func then User.query.filter(func.lower(literal(search_string)).contains(func.lower(User.name)))Try this:
User.query.filter(User.name.match(search_string)) or
User.query.filter(User.name.contains(search_string))
For use in_ you have to use a list, like that:
search_string = ['ed', 'wendy', 'jack']
User.query.filter(User.name.in_(search_string))
