Powershell regex, selection until specific string

Question

I'm not really goot at regex and tried for days to find the right powershell regex for the following situation:
Assuming I have the following input file:
/export/home/ blabla1 blabla2
/export/home/ blabla3 blabla4
/export/home/ blabla5 blabla6
I need a powershell regex expression that separates the selection including /export/home/ until the next /export/home/ appears.
Do you have any ideas?
Thanks in advance

I mean that i like to select everything including /export/home/ until the next /export/home appears. I used to use get-content but it's possible that there are several line breaks until the next /export/home/ appears. As far as i know get-content selects every single line. I would need multiple lines (depending on when /export/home/ shows up) — Royce
– Royce, Commented Oct 23, 2015 at 9:29

Mathias R. Jessen · Accepted Answer · 2015-10-23 15:53:16Z

2

Easiest way to do what you're trying to accomplish is doing a -split with a zero-length delimiter:

(Get-Content .\file.txt -Raw) -split "(?!^)(?=/export/home/)"

The right-hand argument basically says "split when":

(?!^) # not at start of string
(?=/export/home/) # next match is /export/home/

You can remove trailing newlines with TrimEnd():

$Delimiter = '/export/home/'
$Escaped   = [regex]::Escape($Delimiter)
$Split     = "(?!^)(?=$Escaped)"
$Result    = (Get-Content .\file.txt -Raw) -split $Split |ForEach-Object { $_.TrimEnd() }

answered Oct 23, 2015 at 15:53

Mathias R. Jessen

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1 Comment

Royce Over a year ago

Thanks Mathias, that's exactly what I need :)

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