Php if empty variable

Question

So, I have following variables:

<?php
$multi_images = image($image, $rh_post_id);
?>

Then, I want to show something like this only if the variable is not empty. I am not sure what the best way to do it.

<?php if ( empty($multi_images())) { ?>                         
    no images
<?php }else{ ?>
    there is an image
<?php } ?>

Is this correct?

Thanks!

why dont you use echo instead of opening and clogin php tags.. or set the valur of variable in loop first and than display the value of variable — Mike Ross
– Mike Ross, Commented Oct 16, 2015 at 1:12
and i am calling a variable, like a image source (So, it will like numbers) — Steve Kim
– Steve Kim, Commented Oct 16, 2015 at 1:15

user2182349 · Accepted Answer · 2015-10-16 01:19:18Z

2

I'd code it like so, with the assumption that $multi_images is an array of images.

<?php if ( isset($multi_images) && is_array($multi_images) && count($multi_images) > 0) : ?>                         
    no images
<?php else : ?>
    there is an image
<?php endif ?>

answered Oct 16, 2015 at 1:19

user2182349

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1 Comment

Steve Kim Over a year ago

Make sense! =) Thanks

Daryl Gill · Accepted Answer · 2015-10-16 01:17:47Z

1

Are you calling a variable or a function?

 $multi_images;

or

multi_images();

Each one is different. If you want to validate a response from a function you'll use:

if (empty(image($image, $rh_post_id))){  ... }

on a variable:

if (empty($image)){ ... }

to check that the response is not empty. You'll want to use the exclamation mark ! so it'll be:

if (!empty($var)){ .. }

which will translate to

if variable is not empty

answered Oct 16, 2015 at 1:17

Daryl Gill

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