Accessing Element Array with User Input

Question

i'm new in Java and i am trying to make user can get what element from arrays they're asking for.

int[] aksesArray = {30, 50, 10, 90, 70};

So if the user inputs an answer 0, he will get access element 0 which is 30, and so on. And whenever the user inputs 0, 1, 2, 3, 4 the answer will always refer to 30.

i think the problem is on my a = aksesArray.length;

import javax.swing.JOptionPane; 

public class pickingArray {


public static void main(String[] args) {

int[] aksesArray = {30, 50, 10, 90, 70};

int inputElm = Integer.parseInt(JOptionPane.showInputDialog("Input Number to find an Element "));
int a = (inputElm);

a = aksesArray.length;


    if ( a == aksesArray.length ) {
        JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[0] );
    }
    else if ( a == aksesArray[1] ) {
        JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[1] );
    }
    else if ( a == aksesArray.length ) { 
        JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[2] );
    }
    else if ( a == aksesArray.length ) { 
        JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[3] );
    }
    else if ( a == aksesArray.length ) { 
        JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[4] );
    }
    else {
        JOptionPane.showMessageDialog(null, "No Element " );
    }


    }

}

int a=aksesArray[inputElm];

SatyaTNV
– SatyaTNV

2015-10-14 08:51:12 +00:00
Commented Oct 14, 2015 at 8:51 — SatyaTNV
– SatyaTNV, Commented Oct 14, 2015 at 8:51

Tim Biegeleisen · Accepted Answer · 2015-10-14 08:53:34Z

2

You can greatly simplify your code by checking if the input number is within the range of the aksesArray. In either case, you can print an appropriate message.

public static void main(String[] args) {
    int[] aksesArray = {30, 50, 10, 90, 70};

    int inputElm = Integer.parseInt(JOptionPane.showInputDialog("Input Number to find an Element "));

    if (inputElm >= 0 && inputElm < aksesArray.length) {
        JOptionPane.showMessageDialog(null, "Element you are looking for : " + aksesArray[inputElm] );
    }
    else {
        JOptionPane.showMessageDialog(null, "No Element " );
    }
}

answered Oct 14, 2015 at 8:53

Tim Biegeleisen

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3 Comments

pramiezequel Over a year ago

Yes it does simplify the previous codes, thank you for your help.

pramiezequel Over a year ago

how do i mark solved to my question that has been solved ? i'm new on here

Tim Biegeleisen Over a year ago

No you can mark my answer. Click the gray checkmark box and it will turn green. You get 5 points for doing that I think.

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