I am having a string "What is your name?" in a variable like as shown below.
String str="What is your name ?";
String[] splitString =str.split("\\is+");
I want to split the string in such a way that I want only those words between is and ?. ie. your and name by using regular expression
can anyone tell me some solution for this.
You could use something like this:
String str="What is your name ?";
String[] splitString = str.replaceAll(".*? is (.*) \\?", "$1").split(" ");
// [your, name]
Update: if you want to match case insensitive, just add the insensitive flag:
String str="What is your name ?";
String[] splitString = str.replaceAll("(?i).*? is (.*) \\?", "$1").split(" ");
is is case sensitive
(?i).I would do replacing and splitting.
string.replaceFirst(".*\\bis\\b\\s*(.*?)\\s*\\?.*", "$1").split("\\s+");
The poor mans solution would be to extract the substing first and use the split on top of that:
String substring = str.substring(str.indexOf("is")+2,str.indexOf("?"));
String[] splitString =substring.trim().split(" ");
You can use replaceFirst and then split
String str="What is your name?";
String[] splitString =str.replaceFirst(".*[[Ii][Ss]]\\s+","").split("\\s*\\?.*|\\s+");
for (int i=0; i< splitString.length; i++){
System.out.println("-"+splitString[i]);
}
replaceFirst is needed to delete the first part of string, which is What is. The regex .*[[Ii][Ss]]\\s+ means - any signs before case insensitive IS and all the spaces after that. If it'll stay, we will get an additional empty string while splitting.
After replacing, it splits the rest string by
\\s+ one or more whitespaces
and
\\s*\\?.* the ? sign with all whitespaces before and any characters after
Use the regex is([^\?]+) and capture the first subgroup and split it
This is a slightly longer approach, but is the right way to do this in core Java. You can use a regex library to do this
import java.util.regex.Matcher;
import java.util.regex.Pattern;
//Later
String pattern="`is([^\?]+)"
Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(str);
var words=m.group(1)
str.split("\\is([^\?]+)") is giving exception