Javascript Ajax data inside PHP function

Question

I have an Ajax call to create a new Quiz, with a link to the edit page of the quiz (using Laravel)

Now I have inside my JavaScript a PHP function, which therefor has a JavaScript variable again.

How is the variable data.id inserted inside the php asset function?

$('#newQuiz').click(function () {
    var quizName = $('#quiz-name').val();
    var url = "quizzes/store";
    var token = '{{ csrf_token() }}';

    $.ajax({
        type: "POST",
        url: url,
        data: {
            'name': quizName,
            '_token': token
        },
        success: function (data) {
            $('.quiz-table > tbody').append(
                    '<tr>' +
                    '<td>' + data.id + '</td>' +
                    '<td>' + data.name + '</td>' +
                    '<td>' + '<button type="button" class="btn btn-warning"><a href="{{ asset("quizzes/".+data.id+."/questions") }}">Edit Quiz</a></button>' + '</td>' +
                    '<td>' + '<button type="button" class="btn btn-success">Play Quiz</button>' + '</td>' +
                    '</tr>'
            );

            $('#quiz-name').val('');
        }
    });
});

This rule for clarification {{ asset("quizzes/".+data.id+."/questions") }}

You haven't actually posted any PHP, only what looks like some Twig placeholders. In any case, you can't use PHP on JavaScript like this because PHP runs only server-side. — elixenide
– elixenide, Commented Oct 2, 2015 at 12:34

Drown · Accepted Answer · 2015-10-02 12:36:51Z

2

How is the variable data.id inserted inside the php asset function?

You can't. PHP runs on the server, you can't set the value of a PHP variable via Javascript - the opposite is true though.

answered Oct 2, 2015 at 12:36

Drown

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1 Comment

azium Over a year ago

@Drown he could do another ajax call though, I suspect since data.id is being returned by success, it was already in php form first.

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