I have 2 arrays:
$array_1 = [1,2,3,1,2];
and:
$array_2 = [0,0,0,0,0];
I want to change the values of $array_2, so it will show if the element in $array_1 is number 1 or 2 only.
foreach($array_1 as $item)
{
if($item = 1 || $iten == 2)
{
$index = ...;//how to get index of this element
$array_2[$index] = 1; //I don't sure this syntax is right
}
}
Output $array_2 should look like: $array_2 = [1,1,0,1,1]
In Laravel 5 or above, you can do this:
Just pass a array to this function, use a dot notation to handle nested arrays
use Illuminate\Support\Arr;
Arr::set($data, 'person.name', 'Calixto');
Or you can use this Laravel Helpers:
$data = ['products' => ['desk' => ['price' => 100]]];
data_set($data, 'products.desk.price', 200, false);
For more details look at laravel documentation: Laravel Docs Helpers
<?php
// your code goes here
$array_1 = [1,2,3,1,2];
$array_2 = [0,0,0,0,0];
$index = 0;
foreach($array_1 as $item)
{
if($item == 1 || $item == 2)
{
//how to get index of this emlement
$array_2[$index] = 1; //I don't sure this syntax is right
}
else
{
//do nothing
}
$index++;
}
echo "<pre>";
print_r($array_2);
echo "</pre>";
I guess you only want to replace items other than 1, 2 to 0, Correct me if I am wrong.
$array_3 = array();
foreach ($array_1 as $key => $item)
{
if($item == 1 || $item == 2)
{
$array_3[$key] = $item;
}
else
{
$array_3[$key] = 0;
}
}
Try this code
$array_1 = array(1,2,3,1,2);
foreach($array_1 as &$item)
{
if($item = 1 || $item == 2) {
$item = 1;
}
}
echo $array_1;
The following PHP code might do what you intend:
<?php
$valid = [1, 2]; // allows you to extend a bit later
$array_1 = [1,2,3,1,2];
$array_2 = array_map(function($var) use ($valid) {
return in_array($var, $valid) ? 1 : 0;
}, $array_1);
print_r($array_2); // [1, 1, 0, 1, 1]
Take a look at the array_map function at http://php.net/manual/en/function.array-map.php
