Store array into array of array

Question

Im generating Chart4PHP. In sample it takes data like this

$p->data = array(array(array("2010/10",-48),array("2011/01",238),array("2011/02",395)));

I have array "rows" constructed of row[date][units]. Im storing it in this way:

$rows = array();
for(...)
{
$row[date] = $mydate;
$row[units]= $myunits;
$rows[]=$row;
}

What I should make additionally to be able to use it as $p->data = $rows;

Are you sure you need a 3-dimensional array, not 2-dimensional? Do you have a link to the Chart4PHP documentation? — Barmar
– Barmar, Commented Sep 24, 2015 at 19:06

Barmar · Accepted Answer · 2015-09-24 19:39:31Z

1

To add the extra array container, call array() with the rows array as the argument.

$data = array(array('date' => "2010/10", 'units' => -48),
              array('date' => "2011/01", 'units' => 238),
              array('date' => "2011/02", 'units' => 395));

foreach ($data as $d) {
    $mydate = $d['date'];
    $myunits = $d['units'];
    $rows[] = array($mydate, $myunits);
}
$p->data = array($rows);

edited Sep 24, 2015 at 19:39

answered Sep 24, 2015 at 19:12

Barmar

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2 Comments

Rokas Paškevičius Over a year ago

in this way it takes only $mydate to show in the output, it wont read second value of array. If i change $rows[] = array($myunits, $mydate); it shows units (so data is OK).

Barmar Over a year ago

My code should create the exact result that you asked for in the question.

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