json array value is not passed back to jquery

Question

hi i am trying to dynamically validate my registration form, so that check are being made, when the user enters values into input fields using jquery and php. any help would be most appreciated.

html

   <DOCTYPE html>

<html lang="en">

<head>
     <meta charset="utf-8">
     <title>jQuery Tutorial</title>
</head>

<body>
<form>
<input type="text" id="fname" size ="25" placeholder="firstname" />
<span id="fname_feedback"></span></br></br>
<input type="text" id="lname" size ="25" placeholder="firstname" />
<span id="lname_feedback"></span></br></br>
<input type="submit" id="reg" value="sign up">
</form>

<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript" src="js/reg.js"></script>
</body>

</html>

jquery

function validate(fname, lname){
$.post('php/registration.php', {fname: fname, lname: lname}, function(data){

        $('#fname_feedback').text(data.fname);
        $('#lname_feedback').text(data.lname);
;
    },'json');
}

$('#fname').focusin(function(){ 
  if($('#fname').val() ==='') {
$('#fname_feedback').text('requried field');
} else {

validate($('#fname').val());

}
}).blur(function() { 

$('#fname_feedback').text('');

validate($('#fname').val());

}).keyup(function(){

validate($('#fname').val());

});

$('#lname').focusin(function(){ 
  if($('#lname').val() ==='') {
$('#lname_feedback').text('requried field');
} else {

validate($('#lname').val());

}
}).blur(function() { 

$('#lname_feedback').text('');

validate($('#lname').val());

}).keyup(function(){

validate($('#lname').val());

});

php

<?php

require '../init.php';
$fname_error= '';
$lname_error='';

if(isset($_POST['fname']))
{
    $fname = $_POST['fname'];

     //updated if statement
     if (strlen($fname) < 5)
    {
        $fname_error = 'example error message';
    } else {

         $fname_error = 'example';
    } 
}

if(isset($_POST['lname']))
{
    $lname = $_POST['lname'];

     //updated if statement
     if (strlen($lname) < 5)
    {
        $lname_error = 'example error message';
    } else {

         $lname_error = 'example';
    } 
}


$return_data=array('fname'=> $fname_error, 'lname'=>$lname_error);

header('Content-Type: application/json');
echo json_encode($return_data);
exit();
?>

pspatel · Accepted Answer · 2015-09-17 14:41:07Z

3

You need to use parseJSON function of jquery to use return data, so line will be something like this in validate function

var obj = jQuery.parseJSON(data);
$('#fname_feedback').text(obj.fname);

I controller you need to add like this

<?php

require '../init.php';
$fname_error= '';

if(isset($_POST['fname']))
{
    $fname = $_POST['fname'];

     //updated if statement
     if (strlen($fname) < 5)
    {
        $fname_error = 'example error message';
    }
}

$return_data=array('fname'=> $fname_error);

header('Content-Type: application/json');
echo json_encode($return_data);
exit();
?>

edited Sep 17, 2015 at 14:41

answered Sep 17, 2015 at 12:50

pspatel

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7 Comments

percy3872 Over a year ago

i think the error is to do with where i have declared my fname_error variable

pspatel Over a year ago

you need to add this line below the If condition $return_data=array('fname'=> $fname_error);

percy3872 Over a year ago

Thanks but if I had a lot more if statements and I kept pasting it under the if statement wouldn't I just be duplicating code

pspatel Over a year ago

@percy3872 i modified my answer you can check now controller code in this

percy3872 Over a year ago

thanks this passes the data back however when i do an else statement for the fname_ error it does not overide what is currently stored in the fname_error variable

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