underscore finding nested objects

Question

I'm trying to use underscore to find an object in the array which has a child with a certain condition. lets say this is my array:

"array": [
  {
     "user": {
        "profileIcon": 913,
        "id": 62019870
     },
     "count": 1
  },
  {
     "user": {
        "profileIcon": 770,
        "id": 32558522
     },
     "count": 2
  }
]

Now I want to only return an object that has user.id : 62019870. This is the code I have so far but it returns an empty array:

 var arr = _.filter(array, function(obj) {
                return _.findWhere(obj.user, {id: 62019870});
            });

thefourtheye · Accepted Answer · 2015-09-14 05:30:23Z

3

findWhere function works on the array, not on the object. For your case, you can simply do

console.log(_.filter(array, function(obj) {
  return obj.user.id === 62019870;
}));
// [ { user: { profileIcon: 913, id: 62019870 }, count: 1 } ]

If your environment supports, native Array.prototype.filter then you can do the same without underscore, like this

array.filter(function(obj) {
  return obj.user.id === 62019870;
});

If your environment supports ECMA Script 2015's Arrow functions, then you can write the same, more succinctly, like this

array.filter(obj => obj.user.id === 62019870);

edited Sep 14, 2015 at 5:30

answered Sep 14, 2015 at 4:59

thefourtheye

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2 Comments

Mritunjay Over a year ago

I will prefer @alexreardon way, if I don't need to worry about IE8 it's native filter .

thefourtheye Over a year ago

@alexreardon Thanks, included that suggestion also in the answer.

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