Get XML node with specified type in JS

Question

Is there any built in function in JavaScript to get only element nodes, or do I have to add another loop which counts the actual number of those if I need it before, like:

l = 0;
for(i = 0; i < x.childNodes.length; i++){
    if(x.childNodes[i].nodeType = 1) l++;       
}

for(i = 0; i < x.childNodes.length; i++){
    if(x.childNodes[i].nodeType != 1) continue;
    new Something(l);   
}

Try .children instead of .childNodes

user1106925
– user1106925

2015-09-05 16:56:43 +00:00
Commented Sep 5, 2015 at 16:56 — user1106925
– user1106925, Commented Sep 5, 2015 at 16:56

Mads Hansen · Accepted Answer · 2015-09-06 00:15:55Z

1

Node.children is a read-only property that returns a live HTMLCollection of the child elements of Node.

Syntax

var elList = elementNodeReference.children;

elList is a HTMLCollection, which is an ordered collection of DOM elements that are children of elementNodeReference. If there are no element children, then elList contains no elements and has a length of 0.

answered Sep 6, 2015 at 0:15

community wiki

Mads Hansen

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1 Comment

Paweł Audionysos Over a year ago

This is what i wanted but should I change the question title because I accepted the question but it not match the title exactly?

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