create form inside php script

Question

I have a table and use the following to create a button inside one of the cells:

print("<td> <input type=\"submit\" name=\"toedit\" value=\"Submit\" >
    <form action=\"Manage_Customer_Information_refined_list.php\" method=\"post\">
        <input type=\"hidden\" value=\"Submit\" name =\"submit_button\" >
    </form>
</td>");

When i go to call upon the button (press it) using

if(print_r($_POST["\"submit_button\""]))
{
    print "button pressed";
}

It says

undefined index "submit_button"

Please Help :/

There are so many things wrong here. But lets stick to the obvious. print_r is a function with highly mixed return values, it can return a bool, a string, an int, a float, god knows what, it depends on the context. However, to keep this simple, print_r doesn't belong in that if. It should be something like this if(isset($_POST['submit_button'])) — Andrei
– Andrei, Commented Aug 31, 2015 at 11:28

irfanengineer · Accepted Answer · 2015-08-31 11:34:17Z

2

try this

print("<td> 
    <form action=\"Manage_Customer_Information_refined_list.php\" method=\"post\">
        <input type=\"hidden\" value=\"Submit\" name =\"submit_button\" >
        <input type=\"submit\" name=\"toedit\" value=\"Submit\" >
    </form>
</td>");

and if you want to submit on same page then remove Manage_Customer_Information_refined_list.php form form.

answered Aug 31, 2015 at 11:34

irfanengineer

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Comments

Harshit · Accepted Answer · 2015-08-31 11:30:27Z

1

Change

<input type=\"hidden\" value=\"Submit\" name =\"submit_button\" >

to

<input type=\"submit\" value=\"Submit\" name =\"submit_button\" >

Remove

<input type=\"submit\" name=\"toedit\" value=\"Submit\" >

answered Aug 31, 2015 at 11:30

Harshit

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Comments

Ghulam Ali · Accepted Answer · 2015-08-31 11:43:48Z

1

Change your condition to this

if(isset($_POST["submit_button"]))
{
   print "button pressed";
}

answered Aug 31, 2015 at 11:43

Ghulam Ali

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Oussama Elgoumri · Accepted Answer · 2015-08-31 12:07:32Z

1

The code you write <input type=\"hidden\" value=\"Submit\" name =\"submit_button\" > will be evaluated to ... name="submit_button" which means you should access this input value from the server side using $_POST["submit_button"].

The way you did write $_POST["\"submit_button\""] expect the input field to be written as <input type=\"hidden\" value=\"Submit\" name =\"\"submit_button\"\" > and i don't think that this is a valid syntax, also you should put the submit button inside the form not outside of it.

answered Aug 31, 2015 at 12:07

Oussama Elgoumri

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