Using replace and regex to remove characters from this string

Question

I am trying to remove the brackets and 'url' from a string similar to this:

url('http://www.stackoverflow.com');

So it would just leave 'http://www.stackoverflow.com'

The furthest I have got to getting this working is

var myvar = url('http://www.stackoverflow.com');
myvar = myvar.replace(/[url()]/g, '');

But obviously this would mean that any 'u', 'r', or 'l' would be removed from the actual domain.

I guess the answer would be to only remove the first instance of each of the characters.

var myvar = "url('http://www.stackoverflow.com')"; wrap in quotes to make it string. Open browser console to check errors — Tushar
– Tushar, Commented Aug 28, 2015 at 6:52

semirturgay · Accepted Answer · 2015-08-28 07:24:04Z

3

Use capturing group.

var string = "url('http://www.stackoverflow.com')";
var url =   string.replace(/\burl\('([^()]*)'\)/g, "$1")
document.write(url)

edited Aug 28, 2015 at 7:24

semirturgay

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answered Aug 28, 2015 at 6:54

Avinash Raj

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5 Comments

Tushar Over a year ago

The real problem is with the myvar. It is not string that contains url, it is something returned by function url()

Tushar Over a year ago

var myvar = "url('http://www.stackoverflow.com')"; myvar = myvar.replace(/[url()]/g, ''); Execute in console

Avinash Raj Over a year ago

@Tushar ya, it seems like a typo.

Narendrasingh Sisodia Over a year ago

@Tushar I am trying to remove the brackets and 'url' from a string similar to this: Its a string only

Tushar Over a year ago

@NarendraSisodia Can you please read the previous comments here. var myvar = "url('http://www.stackoverflow.com')"; myvar = myvar.replace(/[url()]/g, ''); Execute in console

Wiktor Stribiżew · Accepted Answer · 2015-08-28 06:59:05Z

0

You can use a non-regex replace since you are remove just once:

var myvar = "url('http://www.stackoverflow.com')";
myvar = myvar.replace("url('", '').replace("')", "");
document.write(myvar);

For the regex-iacs:

var myvar = "url('http://www.stackoverflow.com')";
myvar = myvar.replace(/^url\('|'\)$/g, '');
document.write(myvar + "<br/>");

 // or even
var myvar = "url('http://www.stackoverflow.com')";
myvar = myvar.replace(/\bUrl\('|'\)/ig, '');
document.write(myvar);

edited Aug 28, 2015 at 6:59

answered Aug 28, 2015 at 6:53

Wiktor Stribiżew

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2 Comments

Tushar Over a year ago

The real problem is with the myvar. It is not string that contains url, it is something returned by function url()

Wiktor Stribiżew Over a year ago

@Tushar: I believe that is an OP's typo, and it is a string. Otherwise, the original code does not compile.

Imab Asghar · Accepted Answer · 2015-08-28 07:00:47Z

0

Try using string as mentioned by Tushar.

var myvar = "url('http://www.stackoverflow.com')";
myvar = myvar.replace(/[url()]/g, '');

answered Aug 28, 2015 at 7:00

Imab Asghar

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Comments

Guffa · Accepted Answer · 2015-08-28 07:04:36Z

0

If you know that the string always has that format, you don't need to replace, you can just remove the characters from the start and end:

myvar = myvar.substr(5, myvar.length - 8);

answered Aug 28, 2015 at 7:04

Guffa

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