How to match a pattern against an array in JavaScript?

Question

we have $.inArray(searchString, array) function in jQuery, but this will look for the exact match of the string in the values present in the array. But how to check the string in the array like indexOf?

For e.g., Let us take the string "mark_zuck" and if the array looks like this, ["mark", "sheryl", "zuck"]. We can do this by using a loop comparing each value in array with the given string like,

for (i=0; i<array.length; i++) {
    searchString.indexOf(array[i]);
}

I'm looking for a better way to implement this. Please help.

I deleted my comments as it turns out I was wrong! atinder has posted a nearly correct solution. — Reinstate Monica Cellio
– Reinstate Monica Cellio, Commented Aug 20, 2015 at 10:31

atinder · Accepted Answer · 2015-08-20 10:32:39Z

1

array.filter(function(a){
  return searchString.indexOf(a) !== -1;
}

edited Aug 20, 2015 at 10:32

answered Aug 20, 2015 at 10:27

atinder

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4 Comments

Reinstate Monica Cellio Over a year ago

It should be return searchString.indexOf(a) !== -1;

Stranger Over a year ago

@Archer @ atinder Hey, can you take a look of the fiddle, jsfiddle.net/udhayakumar/3v3288s6. Because it is returning ["sheryl", "zuck"] instead of ["mark", "zuck"]. Am I doing something wrong?

Reinstate Monica Cellio Over a year ago

Yes, you've highlighted the reason you need !== -1 at the end. atinder updated the answer to include it, so try what he has above now.

Stranger Over a year ago

@Archer Oops, I didn't notice that. Sorry and thanks :)

Anand G · Accepted Answer · 2015-08-20 11:14:10Z

0

You can use array.some also

var monthNames = ["mark", "sheryl", "zuck"];
var chk = 'mark_zuck';

var test = monthNames.some(function(e) {    
   return chk.indexOf(e);
});
console.log(test);

Fiddle: http://jsfiddle.net/haqk2snr/

answered Aug 20, 2015 at 11:14

Anand G

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