how to pass these strings from php to javascript

Question

i have 4 strings in my application like this that i want to pass to my js file

$a1='[10,20,13,14]';
$a2='[17,15,14,16]';
$a3='[18,24,16,17]';
$a4='[15,54,18,27]';

echo $a1.",".$a2.",".$a3.",".$a4;

and my javascriptcode is

$.ajax({
           type: "POST",
           dataType: "json",
           url: "loaddata.php",
               success: function(data)
            {
           alert(data); //alert 15,54,18,27


          }
     });

i can get just $a4 string, and i can not get other string

how can i pass these 4 strings in php and set these 4 variables in javascript

thanks;

icktoofay · Accepted Answer · 2010-07-04 07:59:13Z

5

Encode them as JSON.

On the PHP side:

echo json_encode(array("a1" => $a1, "a2" => $a2, "a3" => $a3, "a4" => $a4));

On the JavaScript side:

$.ajax({
    type: "POST",
    dataType: "json",
    url: "loaddata.php",
    success: function(data) {
        var a1=data.a1;
        var a2=data.a2;
        var a3=data.a3;
        var a4=data.a4;
        // do something with a1, a2, a3 and a4
    }
});

And if you want a1, a2, a3, and a4 to be arrays of numbers instead of strings containing numbers, just JSON decode the strings on the PHP side before sending them over:

echo json_encode(array(
    "a1" => json_decode($a1),
    "a2" => json_decode($a2),
    "a3" => json_decode($a3),
    "a4" => json_decode($a4)
));

answered Jul 4, 2010 at 7:59

icktoofay

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2 Comments

Erik Escobedo Over a year ago

I don't think it's neccesary to nest the json_encode's. A wrapper json_encode jsonEncodes all the object, doesn't?

icktoofay Over a year ago

@Erik: Yes, but see, I'm not nesting json_encodes. It's decoding them, then re-encoding the complete structure.

Community · Accepted Answer · 2023-11-21 15:10:29Z

1

Use json_encode on the php side and pass the data back that way https://www.php.net/manual/en/function.json-encode.php

edited Nov 21, 2023 at 15:10

CommunityBot

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answered Jul 4, 2010 at 7:56

tsgrasser

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Comments

turbod · Accepted Answer · 2010-07-04 07:56:19Z

0

Use the serialize() method. Pass the variables in a input field and:

$.post("loaddata.php", $("#ajaxform").serialize(), function(data){
  //
});

answered Jul 4, 2010 at 7:56

turbod

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Comments

jigfox · Accepted Answer · 2010-07-04 08:11:10Z

$a1='[10,20,13,14]';
$a2='[17,15,14,16]';
$a3='[18,24,16,17]';
$a4='[15,54,18,27]';

echo $a1.",".$a2.",".$a3.",".$a4;

will return

[10,20,13,14],[17,15,14,16],[18,24,16,17],[15,54,18,27]

this is not a valid JSON string.

You can return an object that contains an array of arrays like this:

echo "[".$a1.",".$a2.",".$a3.",".$a4."]";
// => [[10,20,13,14],[17,15,14,16],[18,24,16,17],[15,54,18,27]]

or you can do return an object with named keys to access the different arrays.

echo "{a1:".$a1.",a2:".$a2.",a3:".$a3",a4:".$a4."};
// => {a1:[10,20,13,14], a2:[17,15,14,16], a3:[18,24,16,17], a4:[15,54,18,27]}

Or even much butter: Don't build the JSON String on your own and use PHP's json_encode instead:

$a1=array(10,20,13,14);
$a2=array(17,15,14,16);
$a3=array(18,24,16,17);
$a4=array(15,54,18,27);

echo json_encode(array($a1,$a2,$a3,$a4));
// => [[10,20,13,14],[17,15,14,16],[18,24,16,17],[15,54,18,27]]
// or if you want an associative array
echo json_encode(array("a1" => $a1, "a2" => $a2, "a3"=> $a3, "a4" => $a4));
// => {a1:[10,20,13,14], a2:[17,15,14,16], a3:[18,24,16,17], a4:[15,54,18,27]}

Nikola K. · Accepted Answer · 2012-11-13 12:54:30Z

0

return "{ A1: '[10,20,13,14]', A2: '[17,15,14,16]', A3: '[18,24,16,17]', A4: '[15,54,18,27]' }";

Though you could also just pass these as actual arrays by removing the quotes.

edited Nov 13, 2012 at 12:54

Nikola K.

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answered Jul 4, 2010 at 7:54

spinon

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