How to Convert Nested array to Value in PHP?

Question

My arrays

a:3:{s:6:"Choice";a:2:{i:0;s:5:"First";i:1;s:6:"Second";}s:5:"fcode";s:26:"form_rajas_exmsw2rpc81anlj";s:9:"useremail";s:26:"[email protected]";}

array (
  'Choice' => 
  array (
    0 => 'First',
    1 => 'Second',
  ),
  'fcode' => 'form_rajas_exmsw2rpc81anlj',
  'useremail' => '[email protected]',
)

my php code

$arrays = 'a:3:{s:6:"Choice";a:2:{i:0;s:5:"First";i:1;s:6:"Second";}s:5:"fcode";s:26:"form_rajas_exmsw2rpc81anlj";s:9:"useremail";s:26:"[email protected]";}';

$decode = unserialize($arrays);
foreach($decode as $key => $value) {
    echo '<td width="100">' . $value . '</td>';
}

My Error is :

Notice: Array to string conversion in....

The first Values in Nested Array.

How to convert nested array as a Value?

I need to show like this,

<tr><td>First,Second</td><td>form_rajas_exmsw2rpc81anlj</td><td>[email protected]</td></tr>

The first Values in Nested Array there is 2 value which are "first" and "second" which you wanna show? — Imtiaz Pabel
– Imtiaz Pabel, Commented Jul 26, 2015 at 7:56
There are many ways to convert nested array as a Value. What is the expected output ? So we can suggest accordingly — Jigar
– Jigar, Commented Jul 26, 2015 at 8:03
There is an edit button. Most easy answear is to use echo '<pre>'; print_r( $decode ); echo '</pre>';. You can also make a recursion function that checks if the input is an array: ifso recall itself with that array, else print the string. — Jeffrey
– Jeffrey, Commented Jul 26, 2015 at 8:18

Barmar · Accepted Answer · 2015-07-26 08:40:38Z

1

If $value is an array, you need a nested loop.

foreach ($decode as $key => $value) {
    if (!is_array($value)) {
        $value = array($valule);
    }
    foreach ($value as $subvalue) {
        echo "<td width='100'>$subvalue</td>";
    }
}

If you can have multiple levels of nesting, you should write a recursive function that handles each level.

If you want a sub-array to be shown as a comma-separated list, you can use implode.

foreach ($decode as $key => $value) {
    if (is_array($value)) {
        $value = implode(', ', $value);
    }
    echo "<td width='100'>$subvalue</td>";
}

edited Jul 26, 2015 at 8:40

answered Jul 26, 2015 at 8:18

Barmar

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5 Comments

Rajasekaran Raji Over a year ago

Thanks, The Results is <td width='100'>First</td><td> Second</td> But I Need <td width='100'>First, Second</td> It is Possible?

Barmar Over a year ago

Use implode for that.

Rajasekaran Raji Over a year ago

It Works $decode = unserialize($arrays); echo'<table><tr>'; foreach ($decode as $key => $value) { if (!is_array($value)) { $value = array($value); } if (is_array($value)) { $value = implode(', ', $value); } echo "<td width='100'>$value</td>"; } echo'</tr></table>';

Barmar Over a year ago

You don't need the first $value = array($value) any more.

Rajasekaran Raji Over a year ago

I change That, $decode = unserialize($arrays); echo'<table><tr>'; foreach ($decode as $key => $value) { if (is_array($value)) { $value = implode(', ', $value); } echo "<td width='100'>$value</td>"; } echo'</tr></table>';

Jayo2k · Accepted Answer · 2015-07-26 08:35:09Z

0

you have nested array populated with elements of diferent size so you will always get an error. so in your foreach loop, you can check if the value is an array or not, like for instance

if (count($value)>1){
//code here like for instance echo $value[0]...
}//not recomended becuse an array can have only one value, but you can if you know you will put at least 2

or

if(is_array($value)..

Me I will do the following:

foreach($thing as $thingy =>$that){
   //check if array or not
   if(is_array($that)){
       foreach($that as $t)
             //do whatever
   }else
      //do whatever
}

edited Jul 26, 2015 at 8:35

answered Jul 26, 2015 at 8:29

Jayo2k

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