Maybe a weird question. Say I have code like this:
def foo():
print "Foo"
def bar(x):
print x
func = foo
func()
func = bar
arg = 'a'
func(arg)
is there a way to have an "empty" argument, so that I can call assign foo() to func and then still call func(arg)?
Not just a workaround like
if arg is None:
func()
else:
func(arg)
Sure, if you use tuples/lists and argument unpacking.
def foo():
print "Foo"
def bar(x):
print x
args = ()
func = foo
func(*args)
func = bar
args = ('a',)
func(*args)
Result:
Foo
a
Yes, use the splat operator
args = []
func = foo
func(*args)
func = bar
args = ["Hello world!"]
func(*args)
"Hello World!"
You can even use dictionaries to do this sort of thing
funcs = (foo, bar)
func_dict = {func.__name__: func for func in funcs}
args = []
func_dict["foo"](*args)
try this
def foo(arg=None):
print "Foo"
or use this
def foo(*arg):
print "foo"
then you may call it how ever you want
arg = 'a'
func = foo
func(arg)
func = bar
func(arg)
or as others have pointed out use
arg=()
func=foo
func(*arg)
arg=('hello',)
func(*arg)
