AngularJS While Add location parameter it should maintain previously inserted

Question

When i add parameter using $location in url as shown below it first removes added data but i want to keep that previous data...

Example with code

when i do this,

$location.path('/bag_list').search({category: cat_search});

it simply changes url to this,

now when next function doing something like this,

$location.path('/bag_list').search({model: model_search});

and then url changes to this,

but i want to keep both like this,

I WANT LIKE THIS: http://localhost/angular_laravel/angjs/#/bag_list?model=1&category=1

My problem is that it deletes previous parameter but i want to keep that parameter,

any help...??

Brenton Alker · Accepted Answer · 2015-07-22 06:57:43Z

3

You have 2 options I believe.

If you are only setting a single value (as you are in the example) you can use the 2 argument form of the setter. eg.

$location.search('model', model_search);

If you need to set more than 1 (or your data is coming in as an object already) you can manually merge the values. eg.

$location.search(angular.extend({}, $location.search(), { model: model_search }));

answered Jul 22, 2015 at 6:57

Brenton Alker

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1 Comment

$location.search(angular.extend({}, $location.search(), { model: model_search })); it make a huge sense about my programming life

Gonz · Accepted Answer · 2015-07-22 06:53:05Z

0

Try:

$location.path('/bag_list').search({category: cat_search, model: model_search});

answered Jul 22, 2015 at 6:53

Gonz

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