Javascript 3D array and .split() method

Question

    function parser(data){
    var saveSections = data.split("\r");
    var parsed = new Array();
    var tempCatch = "";
    var CatchTwo = [];
    //saveSections[0] = saveSections[0].split(",");
    for (var i = 0; i < saveSections.length; i++){
        saveSections[i] = saveSections[i].split(",");
        for (var j = 0; j < saveSections.length; j++){
            tempCatch = saveSections[0][0].split(":");
            //saveSections[0][0] = tempCatch;

        }

    }
    return tempCatch;
}

Ok there is problem. This function works without problems until I uncomment

//saveSections[0][0] = tempCatch;.

When I do it, debbuger throws:

Uncaught TypeError: saveSections[0][0].split is not a function

That points at this line:

tempCatch = saveSections[0][0].split(":");

You've to iterate the third depth too, arrays have not split method. — Teemu
– Teemu, Commented Jul 12, 2015 at 17:03
But I'm spliting elemment of 2D array. It will be 3D AFTER splitting. — Michael Kurowski
– Michael Kurowski, Commented Jul 12, 2015 at 17:06
It contains chars that will not be shown here. It's part of encryption algorithm. :( D:Ch,XPL:1,XPS:987654321,XPE:987654320,E:0,C:2,AC:1,P:0,G:,A:1,S:1,HC:1,H:1,SCO:1,SCR:1,K:2,B:0,BT:0,IP:94.231.225.11,ID:0,IS:1,CM:0D:Eq,I:1,T:1,L:1,C:BBAAD:Eq,I:2,T:2,L:1,C:QIAAD:In,I:25,T:7,Q:30D:Op,M:1,S:1,P:1D:SP,S:BBBBBBBB — Michael Kurowski
– Michael Kurowski, Commented Jul 12, 2015 at 17:11

Vale · Accepted Answer · 2015-07-12 17:28:01Z

1

From the sample data you gave, the problem is that you're always assigning tempCatch to the first item in the 2D array (saveSections[0][0]), at the second iteration the split() function fails because that's an array, not a string.

This code should iterate on all items:

function parser(data){
    var saveSections = data.split("\r");
    var parsed = [];
    var tempCatch = "";
    var CatchTwo = [];
    for (var i = 0; i < saveSections.length; i++){
      saveSections[i] = saveSections[i].split(",");
      for (var j = 0; j < saveSections[i].length; j++){
          tempCatch = saveSections[i][j].split(":");
          saveSections[i][j] = tempCatch;
      }
    }
    return saveSections;
}

I would assume you need to return saveSections instead of tempCatch, but that's a bit unclear from your implementation.

answered Jul 12, 2015 at 17:28

Vale

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