Passing variable in Javascript

Question

What is wrong with this code?

<script type="text/javascript">

   var urlquery = location.href;
   var urlparts = urlquery.split('='); 
   var urlplan  = (urlparts[1]);      

   $(document).ready(function() {
      $('#LDF a').click(function() {  
         $.ajax({
            url: 'src/ldf_dpd_list.php?search-n=urlplan',
            success: function (data) {
               $('#dpd').html(data);
            }
         });
      });
   });

Hi I am new to javascript and Ajax and trying to pass the variable urlplan, what is the correct way to pass the variable.

Are you trying to bold that variable or is your code like that? — alex
– alex, Commented Jun 28, 2010 at 6:33

Daniel Vassallo · Accepted Answer · 2010-06-28 08:12:58Z

4

It looks like the following should do it:

var urlparts = urlquery.split('='); 
var urlplan  = urlparts[1];

// ...

$.ajax({
   url: 'src/ldf_dpd_list.php?search-n=' + urlplan,
   success: function (data) {
      // ...
   }
});

edited Jun 28, 2010 at 8:12

answered Jun 28, 2010 at 6:33

Daniel Vassallo

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Comments

Salil · Accepted Answer · 2010-06-28 06:33:20Z

0

url: "src/ldf_dpd_list.php?search-n="+urlplan,

for more than one variable

url: "src/ldf_dpd_list.php?search-n="+urlplan+"&amp;xyz="+variablName,

answered Jun 28, 2010 at 6:33

Salil

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Comments

Sean Kinsey · Accepted Answer · 2010-06-28 08:13:25Z

0

This is a snippet from my easyXDM library

var _query = (function(){
    var query = {}, pair, search = location.search.substring(1).split("&"), i = search.length;
    while (i--) {
        pair = search[i].split("=");
        query[pair[0]] = pair[1];
    }
    return query;
}());

Use it like this

alert(_query["urlplan"]);

or

alert(_query.urlplan);

answered Jun 28, 2010 at 8:13

Sean Kinsey

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