Parse.com Cloud Code error : TypeError: Cannot call method 'get' of undefined

Question

It is obvious that "result" is coming back as null from the query. If that is the case, why is it calling the "success" routine? I know that the course I am searching for does exist.

Any ideas?

var query = new Parse.Query("Courses");
var CourseObj = new Parse.Object("Courses");

query.equalTo("courseIdFromIOS", request.params.courseIdFromIOS);
query.first({
    success: function (result) {
        CourseObj = result;
        response.success("course lookup good for: " + CourseObj.get("courseName"));
    },
    error: function () {
        response.error("course lookup failed");
    }
});

Not finding something isn't an error if the request was valid... — Wain
– Wain, Commented Jun 29, 2015 at 6:48

Technoid · Accepted Answer · 2015-06-29 10:05:49Z

3

A query always enters success loop if we are able to connect to Parse servers and searched through all the rows even if our query was unsuccessful since there is no error code corresponding to unsuccessful query .Once check this guide and also error codes section. https://www.parse.com/docs/js/guide#handling-errors

So in your case result is undefined

var query = new Parse.Query("MyClass");
var tmp = new Parse.Object("MyClass");

query.equalTo("username", "This does not exist in table");
query.first({
    success: function (result) {
        tmp = result;
        alert("hii");
        alert("course lookup good for: " + tmp.get("name"));
    },
    error: function () {
        alert("helloooo");
    }
});

Even in the above code it is entering success loop

answered Jun 29, 2015 at 10:05

Technoid

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1 Comment

phil Over a year ago

Thank you! Understand. My challenge is to now discover why the query is not finding the record that I know exists. Will update here when I get to the bottom of it.

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