How to find css files with regex

Question

I need to find all the css references in a piece of code with regex

Suppose I have:

<link rel="stylesheet" type="text/css" href="mystyle.css">

The result of the match should be mystyle.css For now I only have ~href=\'.*\.css.*\'~ which matches the entire reference so it's not ok.

Better use DOM not regex

anubhava
– anubhava

2015-06-16 11:24:45 +00:00
Commented Jun 16, 2015 at 11:24 — anubhava
– anubhava, Commented Jun 16, 2015 at 11:24
Why do you need to use a regex for this?

legoscia
– legoscia

2015-06-16 12:09:52 +00:00
Commented Jun 16, 2015 at 12:09 — legoscia
– legoscia, Commented Jun 16, 2015 at 12:09

Alp · Accepted Answer · 2015-06-16 11:37:05Z

2

Karthik's answer is "almost" correct.

I made a "little" change in his example, which now also catches urls like:

http://blah.com/style.css

Modified regex is as follows:

~(?<=href=")[^"]+\.css~

answered Jun 16, 2015 at 11:37

Alp

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karthik manchala · Accepted Answer · 2015-06-16 11:29:34Z

1

You can use the following:

~(?<=href=")[^."]+\.css~

See DEMO

answered Jun 16, 2015 at 11:29

karthik manchala

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legoscia · Accepted Answer · 2015-06-16 12:19:21Z

0

There is no good reason to use a regex for this. Read in the HTML file as a DOM document, and extract the stylesheet references with Xpath:

<?php

$doc = new DOMDocument();
$doc->loadHTMLFile("test.html");

$xpath = new DOMXpath($doc);

$stylesheets = $xpath->query("//link[@rel='stylesheet']/@href");

if ($stylesheets->length == 0) {
    echo "nothing found!\n";
} else {
    foreach ($stylesheets as $stylesheet) {
        echo "found stylesheet: " . $stylesheet->nodeValue . "\n";
    }
}

?>

That is, for each link element in the document (the //link part) where the rel property is stylesheet ([@rel='stylesheet']), extract the href attribute (/@href).

answered Jun 16, 2015 at 12:19

legoscia

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