Scala map split input to int and string?

Question

Normally if I am reading a line of input from stdin that looks like "100 200" I can store them both as ints with this line:

val Array(a, b) = readLine.split(" ").map(_.toInt);

But what if a is an integer and b is a string?

well if the types are different you cannot store them in an homogeneous container such as an Array. If you know the cardinality just put them in variables — Gabriele Petronella
– Gabriele Petronella, Commented Jun 10, 2015 at 18:29

Gabriele Petronella · Accepted Answer · 2015-06-10 18:33:56Z

2

You cannot store values of different types into an homogeneous container such as an Array. If you know the cardinality, just store them in separate variables.

val input = "100 foo"
val Array(a, b) = input.split(" ")

val p1 = scala.util.Try(a.toInt)
val p2 = b

I used scala.util.Try because toInt may fail and throw an exception

answered Jun 10, 2015 at 18:33

Gabriele Petronella

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Maxim · Accepted Answer · 2015-06-10 21:00:56Z

-1

val readLine = "100 foo"
val (int, str) = readLine.split(" ") match {case Array(i, s) => (i.toInt, s)}

answered Jun 10, 2015 at 21:00

Maxim

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