Merge array values for same keys inside loop with php

Question

Going through foreach loop for filter on my site I get array back like this:

Array
(
    [21] => Blau
    [24] => Azul
    [28] => Blue
)

By choosing next filter another array will be created:

Array
(
    [21] => Grün
    [24] => Verde
    [28] => Green
)

and so on...

What I what to do is merge values of these arrays on same keys. So it have to be look like this:

Array
( 
    [21] => Blau-Grün
    [24] => Azul-Verde
    [28] => Blue-Green
)

It worked with Uchiha's code. I made some changed inside my loop:

foreach (...){
    //some logic before 
    $array[] = array();
    $i = 0;
    foreach($array as $k => $v){
        $i++;
        foreach($array[$k] as $key => $value){
            if(array_key_exists($key, $array[$i])){
                $result[$key] = $value . '-' . $array[$i][$key];
            }
        }
    }
    echo '<pre>' . print_r($result,true) . '</pre>';
}

@Rizier123 Yes, I did. I can't make any of suggestions work in my case. I think my problem is: I can't separate described arrays to different varaibles (like &array1 and $array2 etc). Each of these arrays will be produced while foreach loop and saved in same varaiable. — alex
– alex, Commented Jun 10, 2015 at 11:58

user2182349 · Accepted Answer · 2015-06-10 11:47:59Z

3

$maxItems = max(count($blue),count($green));

for ($i = 0; $i < $maxItems; $i++) {
    if (isset($blue[$i], $green[$i])) {
        $combined[$i] = $blue[$i].'-'.$green[$i];
    } else {
        if (isset($blue[$i])) {
            $combined[$i] = $blue[$i];
        } else {
            $combined[$i] = $green[$i];
        }
    }
}

edited Jun 10, 2015 at 11:47

answered Jun 10, 2015 at 11:32

user2182349

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2 Comments

user2182349 Over a year ago

Thank you Uchiha - I added the missing right brace.

Narendrasingh Sisodia Over a year ago

Even though your output is not meeting OPs output Check This

Narendrasingh Sisodia · Accepted Answer · 2015-06-10 11:33:06Z

1

You can use foreach along with array_key_exists as

foreach($arr1 as $key => $value){
    if(array_key_exists($key, $arr2)){
        $result[$key] = $value.'-'.$arr2[$key];
    }
}

Fiddle

answered Jun 10, 2015 at 11:33

Narendrasingh Sisodia

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Comments

wmk · Accepted Answer · 2015-06-10 11:38:53Z

0

you can use array_map with a closure that joins the two values, e.g.

$joined = array_map(function($m, $n){ return $m . '-' . $n; }, $array1, $array2);

answered Jun 10, 2015 at 11:38

wmk

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1 Comment

jvk Over a year ago

Hi @wmk, i checked your solution, but i have noticed that if array2, have more than array1 it is appending(not matching is also adding), but here should not append, can you pls check it out.

Sachin I · Accepted Answer · 2015-06-10 11:39:09Z

0

$foo = array(1 => "Bob", 2 => "Sepi");
$bar = array(1 => "sach", 2 => "john");

$foobar= array();
foreach ($foo as $key => $value) {
  foreach ($bar as $key1 => $value1) {
   if($key == $key1){
  $foobar[] = $value."-".$value1;
  }
}}

answered Jun 10, 2015 at 11:39

Sachin I

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Comments

kamal pal · Accepted Answer · 2015-06-10 11:44:59Z

0

You can create a function, which takes both of arrays as parameter and identify which one has more elements, loop through and concat the string from another array at the same key.

$array1 = array(
    'Blau',
    'Azul',
    'Blue'
);

$array2 = array(
    'Grün',
    'Verde',
    'Green'
)

function mergeArray($array1, $array2){
    $newArray = array();
    if(count($array1) >= count($array2)){
        foreach($array1 as $key => $value){
                $newArray[] = $value .  (array_key_exists($key, $array2) ? '-' . $array2[$key] : '');
        }
    } else {
        foreach($array2 as $key => $value){
                $newArray[] = $value .  (array_key_exists($key, $array1) ? '-' . $array1[$key] : '');
        }
    }
}
$newArray = mergeArray($array1, $array2);

$newArray contains the result you expected.

edited Jun 10, 2015 at 11:44

answered Jun 10, 2015 at 11:31

kamal pal

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1 Comment

PEM Over a year ago

This will not work. Nothing garantee that both arrays have the same number of values, also putting a count() in a loop is not recommended as it slows down the loop. if array 1 is bigger than array 2 your code will break.

kevin · Accepted Answer · 2015-06-10 11:59:22Z

0

here is simple and tested code

<?php
$a1=array(
    1 => 'Blau',
    2 => 'Azul',
    3 => 'Blue'
);
$a2=array
(
    1 => 'Grün',
    2 => 'Verde',
    4 => 'Green'
);
$a3=$a1 + $a2; 
$a4=$a2 + $a1;

foreach($a3 as $key=>$val){
    if($a4[$key] != $a3[$key]){
        $a3[$key] = $a3[$key].' '.$a4[$key];
    }
}
print_r($a3);
?>

answered Jun 10, 2015 at 11:59

kevin

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