Is there any way to set explicit type to object field in php? Something like this
class House{
private Roof $roof
}
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5 Answers
Nope, there isn't. PHP variables can always be of any type. But you can enforce a type in the setter:
public function setRoof(Roof $roof) {
$this->roof = $roof;
}
3 Comments
svens
Note that you can only enforce objects or arrays, but not "primitive" types like float or string.
user229044
Had you a setter that expected a primitive type,
bool for example, you could always assert('is_bool($value)');.
Bill Karwin
@svens: FWIW, PHP development added scalar type hinting on 5/20/2010. I'm not sure when that will make it into an official release, though.
You can't use PHP code to declare the type of an object field.
But you can put type hints in docblock comments:
class House{
/**
* @var Roof
*/
private $roof
}
This still doesn't make the code enforce types, but some IDE tools understand the docblocks and may warn you if you use this variable without conforming to the type hint.
Comments
You're looking for PHP's Type Hinting. It works great on function/method calls. Here's the manual:
Comments
Why not just assign $roof to a new Roof()?
Comments
you could also use the following before using the member
if (!$this->roof instanceof Roof) {
throw new Exception('$this->roof is not an instance of Roof');
}
Comments
