I need a regex that can actually get any number that is inserted after "ab" and "cr". For example, I have a string like this:
rw200-208-ab66
fg200-cr30-201
I need to print ab66 and cr30.
I have tried using strpos:
if (strpos($part,'ab') !== false) {
$a = explode("ab", $part);
echo 'ab'.$a[1];
}
That does not work for the second item.
You could use \K to discard the previously matched chars from printing at the final. The below regex would give you the number which exists next to ab
or cr.
(?:ab|cr)\K\d+
To get the number with alphabets also, use
preg_match_all('~(?:ab|cr)\d+~', $str, $match);
(?:ab|cr)(\d+) use this regex and then get the number from group index 1.Use this regex:
(?>ab|cr)\d+
See IDEONE demo:
$re = "#(?>ab|cr)\d+#";
$str = "rw200-208-ab66\nfg200-cr30-201";
preg_match_all($re, $str, $matches);
print_r($matches[0]);
Output:
Array
(
[0] => ab66
[1] => cr30
)
