Removing form array element

Question

I have a form which has same products but with different attributes. The form looks something similar to this:

<form>
<table>
    <tr>
        <td> Line-1 </td>
        <td> <input type='text' name='ítem[1][Size]'</td>
        <td> <input type='text' name='ítem[1][Color]'</td>
        <td> <input type='text' name='ítem[1][Price]'</td>
    </tr>
    <tr>
        <td> Line-2 </td>
        <td> <input type='text' name='ítem[2][Size]'</td>
        <td> <input type='text' name='ítem[2][Color]'</td>
        <td> <input type='text' name='ítem[2][Price]'</td>
    </tr>
    <tr>
        <td> Line-3 </td>
        <td> <input type='text' name='ítem[3][Size]'</td>
        <td> <input type='text' name='ítem[3][Color]'</td>
        <td> <input type='text' name='ítem[3][Price]'</td>
    </tr>
    <tr>
        <td> Line-4 </td>
        <td> <input type='text' name='ítem[4][Size]'</td>
        <td> <input type='text' name='ítem[4][Color]'</td>
        <td> <input type='text' name='ítem[4][Price]'</td>
    </tr>
    </table>
</form>

PHP Sample Code:

for($i = 0;$i < count($_POST);$i++){
    var_dump($_POST[$i]);
}

Error:

Notice: Undefined offset: 0 in C:\xampp\htdocs\test\testing.php on line 5

If I was to remove item[2] dynamically using js, on submit php would throw an error because it cant find number 2. How could go about this?

Perhaps I'm not doing it right?

Can you show us What are you doing here? It's hard to tell anything without code — RNK
– RNK, Commented May 4, 2015 at 20:38
We need to see what your PHP Code is doing. Please edit and post your PHP form handler. What is the error you're getting. — Twisty
– Twisty, Commented May 4, 2015 at 20:40
Because you are violating array indexes. And please put your error here? — Death-is-the-real-truth
– Death-is-the-real-truth, Commented May 4, 2015 at 20:40
I'm not sure what other code i could write in. I have a form, which gets processed in php using post, In php, if I would write foreach(), it would throw an error because it cant find number 2 so it cant carry on. I will try adding snippet — Vilius
– Vilius, Commented May 4, 2015 at 20:42
@Vilius I'm assuming you're using for not foreach. foreach will never produce an undefined index error. — Mike
– Mike, Commented May 4, 2015 at 20:45

Twisty · Accepted Answer · 2015-05-04 21:34:16Z

5

In your PHP Code, use foreach as has been suggested:

foreach($_POST['item'] as $item){
    echo $item['Size'] . "<br />";
    echo $item['Color'] . "<br />";
    echo $item['Price'] . "<br />";
    echo "<hr />"
}

EDIT:

Another question how would i go about re-changing row numbers once I deleted row number 2?

This is done in JS or JQuery. Something like:

var i = 1;
$.each($("tr"), function(){
  $(this).next("input[name*='Size']").attr("name", "item[" + i + "][Size]");
  $(this).next("input[name*='Color']").attr("name", "item[" + i + "][Color]");
  $(this).next("input[name*='Price']").attr("name", "item[" + i + "][Price]");
  i++;
});

edited May 4, 2015 at 21:34

answered May 4, 2015 at 20:56

Twisty

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