As previously pointed out
product_areas = [["1", "2", "3"], ["3", "1", "2"]].flatten.uniq
-OR-
product_areas.flatten.uniq!
will both lead you to your desired answer.
Why?
When you were running "product_areas.uniq!" the process was comparing the two inner arrays against each other, other than the elements of each array. Because both ["1", "2", "3"] and ["3", "1", "2"] are unique in the array, neither will be removed. As an example say you had the following array
product_areas = [["1", "2", "3"], ["3", "1", "2"], ["1","2","3"]]
and you ran:
product_areas = product_areas.uniq
product_areas would then look like the following:
product_areas = [["1", "2", "3"], ["3", "1", "2"]]
What you need to be aware of when running any sort of enumerable method on arrays is it will only move down to each individual element. So if inside an array you have more arrays, any iterative method will look at the inner array as a whole. Some sample code to demonstrate this:
array_of_arrays = [[1,2,3], [4,5,6]]
array_of_arrays.each do |array|
p array
end
#---OUPUT---
# [1, 2, 3]
# [4, 5, 6]
array_of_arrays.each do |array|
array.each do |element|
p element
end
end
#---OUPUT---
# 1
# 2
# 3
# 4
# 5
# 6
[[1,2,2],[2,1,2]]=> [1,2]` and[[1,2,2],[2,1,3]]=> [1,2,3], or[[1,2,2],[2,1,2]]` => [1,2,2]` and[[1,2,2],[2,1,3]] => [[1,2,2],[2,1,3]], or something else? Please answer by editing the question, rather than explaining in comments.