Php validation error when form submit

Question

The following code does not work as intended, when the submit button of the form is clicked it with no data entered it goes to blog.php instead of showing the error above the form?

<?php 

session_start();

include_once('connection.php');



if (isset($_SESSION['logged_in'])){
    //display index
} else {
    if (isset($_POST['username'], $_POST['password'])) {
        $username = $_POST['username'];
        $password = $_POST['password'];

        if (empty($username) or empty($password)) {
            $error = 'All fields are required!';
        }
    }
}
?>

linked with the following html form

  <?php if (isset($error)) { ?>
    <small style="color:#aa0000;"><?php echo $error;  ?> </small>
  <?php } ?>


  <form action="blog.php" method="post">
    <input type="text" name="username" placeholder="username" />
    <input type="password" name="password" placeholder="password" />
    <input type="submit" value="login" />
  </form>

You could redirect back to the login page from the PHP that tests for the two inputs with a header('Location: login.php?error='.$error) if an error occurs. — user2182349
– user2182349, Commented Apr 30, 2015 at 0:32
It won't receive a value because blog.php doesn't know the variable $error from admin.php — DigitalDouble
– DigitalDouble, Commented Apr 30, 2015 at 0:35

Saagar Elias Jacky · Accepted Answer · 2015-04-30 00:36:51Z

1

If the actual validation is being done in admin.php, shouldn't the action be pointing to admin.php?

  <?php if (isset($error)) { ?>
    <small style="color:#aa0000;"><?php echo $error;  ?> </small>
  <?php } ?>


  <form action="admin.php" method="post">
    <input type="text" name="username" placeholder="username" />
    <input type="password" name="password" placeholder="password" />
    <input type="submit" value="login" />
  </form>

answered Apr 30, 2015 at 0:36

Saagar Elias Jacky

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