json object to array not referencing values

Question

I'm doing something stupid and can't figure it out.

I'm pulling setting details stored in a mysql database as a json object and then converting them to an array.

$settings = (array)json_decode($user['settings']);

I can print_r() this to the following:

Array
(
    [2] => 1
    [1] => 1
)

Good so far.

If I try to update one of the settings, so for example changing 1 to equal 0, I get this:

Array
(
    [2] => 1
    [1] => 1
    [1] => 0
)

I'm doing this simply with this:

$settings[1] = 0;

Ultimately I'm trying to unset the value if it's a 0 and then update the database. Instead of updating the value, it's creating a new entry and using unset doesn't do anything.

What am I doing wrong??

full code snippet for reference:

$settings = (array)json_decode($user['settings']);
print_r($settings);

if(isset($form['usr'][$user['id_user']])){
    $settings[1] = 1;
}else{
    $settings[1] = 0;
    unset($settings[1]);
}

print_r($settings);

returns:

Array
(
    [2] => 1
    [1] => 1
)
Array
(
    [2] => 1
    [1] => 1
    [1] => 0
)

BGH · Accepted Answer · 2015-04-28 23:32:13Z

1

Hi can you add secent param true to function json_decode like that :

$settings = json_decode($user['settings'], true);

I think this fix problem

answered Apr 28, 2015 at 23:32

BGH

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Comments

geoffreybans · Accepted Answer · 2015-04-29 00:27:44Z

0

For one, I see a syntax error in your code. Is it a typing error or it is part of the actual code you did run? This line to unset ->

unset($settings[1];)

The statement termination ";" should be outside as this

unset($settings[1]);

Here is what I have tried. Assuming the $user['settings'] is formed this way

$user['settings'] = array('2' => 1, '1' => 1);

And was turned to json object in this manner

json_encode($user['settings']);

Then the following code should work

$settings = (array)json_decode($user['settings']);
print_r($settings);

if(... true)
{
   $settings[1] = 1;
}
else
{
    $settings[1] = 0;
    unset($settings[1]);
}

print_r($settings);

Should output

Array
(
   [2] => 1
   [1] => 0
)

and

Array
(
    [2] => 1
)

answered Apr 29, 2015 at 0:27

geoffreybans

441 silver badge9 bronze badges

3 Comments

TH1981 Over a year ago

thanks for pointing out the typo; I typed too fast and have amended.

TH1981 Over a year ago

yep. working with the answer from user3146300 - it was the option that needed to be set to force it to convert to an associative array in the json_decode

geoffreybans Over a year ago

okay good. i tested both the casting and setting the second param to true and both worked fine with my code. anyway good if u've answer.

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