How to declare a variable accessible to whole function in angularjs?

Question

(function (angular) {
'use strict';

angular
    .module('app')
    .controller('ListSharedContentCtrl', ['$scope','$log','UserService', 'ContractService','ContentOwnerService','PlatformPartnerService',function ($scope, $log, userService, contractService,contentOwnerService,platformPartnerService) {
        $scope.init = function () {
            var contractIds =[];
           var contentOwnerId;
            var platformPartnerId;
            var user=userService.getCurrentUser('true');
            var contentOwner=userService.isCurrentUserIsContentOwner();
            var platformPartner=userService.isCurrentUserIsPlatformPartner();
            if(contentOwner == "true")
            {
                contentOwnerService.getContentOwnerId().then(function(savedContentOwnerId) {

                 contentOwnerId=savedContentOwnerId;
                 console.log(contentOwnerId);//here I can log the value

                },function(error) {
                    $log.error("Error fetching contract id:" + error.message);
                });
            }
        console.log(contentOwnerId); //but Here I cant log the value..Its showing undefined  
       } $scope.init();
    }]);
  })(angular);

Now my question is how to make the scope of the variable "contentOwnerId" available to whole function?Please anyone help me I cant figure it out..Thanks in advance..!

Yes how to make variable's scope available to whole init() method — Sharathreddy
– Sharathreddy, Commented Apr 21, 2015 at 4:24

jmargolisvt · Accepted Answer · 2015-04-21 02:56:35Z

2

You are declaring contentOwnerId twice; once inside the if block, once outside it. The one outside is declared, but never assigned a value. It should be null where it is showing null.

answered Apr 21, 2015 at 2:56

jmargolisvt

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3 Comments

Sharathreddy Over a year ago

if I doesnt decalre again will it retain the stored value

Sharathreddy Over a year ago

I have made the cahnges as you said but still its not working

datamosh Over a year ago

I can see only one declaration of contentOwnerId, and then, inside the resolved promise, savedContentOwnerId is assigned to it.

datamosh · Accepted Answer · 2015-04-21 08:50:28Z

1

The reason why you are getting the contentOwnerId undefined is that it is undefined until when the getcontentOwnerId() promise succeed!

if you do

var contentOwnerId = "before resolving the promise";

at the beginning of your init() you will probably have that string logged to console, instead of undefined

answered Apr 21, 2015 at 8:50

datamosh

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Comments

Arepalli Praveenkumar · Accepted Answer · 2015-04-21 09:03:32Z

0

use $scope.contentOwnerId instead of var contentOwnerId.

See $scope.contentOwnerId is available to whole controller i.e ListSharedContentCtrl.

normal javascript variable are limited to functions where as $scope is available to entire CONTROLLER

answered Apr 21, 2015 at 9:03

Arepalli Praveenkumar

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Comments

Michael · Accepted Answer · 2015-04-21 10:43:35Z

0

The .then() method belongs to a promise. This means it won't be executed immediately, but later in the angular life cycle.

Your console.log() will always log 'undefined' because your variable won't be initialized there. You can try this to log the value:

$scope.$watch( 
    function() { return contentOwnerId; }, 
    function(newContentOwnerId, oldContentOwnerId) {
        console.log(newContentOwnerId);
    }
);

answered Apr 21, 2015 at 10:43

Michael

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1 Comment

Sharathreddy Over a year ago

Where to implement this code..I understood that the value may not be initialized early because I m resolving it from a promise.Is there any method to bind the value to contentOwnerId as soon as the promise is resolved..?

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