How to exit a program with an exit code: Java

Question

I have an application in Java. I'd like to specify the "exit code" of my console application. How can I apply an exit code for the registerButton?

final JTextField passwordText = new JTextField(20);
passwordText.setBounds(10, 120, 160, 25);
panel.add(passwordText);

JButton loginButton = new JButton("OK");
loginButton.setBounds(10, 150, 80, 25);
panel.add(loginButton);

JButton registerButton = new JButton("CANCEL");
registerButton.setBounds(180, 150, 80, 25);
panel.add(registerButton);

loginButton.addActionListener(new ActionListener() {

    @Override
    public void actionPerformed(ActionEvent actionEvent) {
        int i=Integer.parseInt(passwordText.getText());
        if(1<=i &&i<4) {
            JTextField xField1 = new JTextField(5);
            JTextField xField2 = new JTextField(5);
            JTextField xField3 = new JTextField(5);
            JTextField xField4 = new JTextField(5);

Why create JTextFields in actionPerformed(ActionEvent actionEvent)? — tonychow0929
– tonychow0929, Commented Apr 20, 2015 at 13:43

Leon · Accepted Answer · 2015-04-20 13:36:35Z

2

From what I understand you want to terminate with an exit code

System.exit(status);

answered Apr 20, 2015 at 13:36

Leon

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3 Comments

Kei Over a year ago

hi, i have add system,exit(0) under panel.add(registerButton). but my java application not showing..

Leon Over a year ago

Not showing what? Is it not showing the exit code when it terminates?

Tom Over a year ago

@Kei Please read what System.exist() does, then you will know what happens if you add that line in your "normal" program flow.

Victor Ribeiro da Silva Eloy · Accepted Answer · 2015-04-20 13:37:05Z

2

you can use System.exit(0)

public static void exit(int status) Terminates the currently running Java Virtual Machine. The argument serves as a status code; by convention, a nonzero status code indicates abnormal termination. This method calls the exit method in class Runtime. This method never returns normally.

The call System.exit(n) is effectively equivalent to the call:

Runtime.getRuntime().exit(n) Parameters: status - exit status. Throws: SecurityException - if a security manager exists and its checkExit method doesn't allow exit with the specified status. See Also: Runtime.exit(int)

answered Apr 20, 2015 at 13:37

Victor Ribeiro da Silva Eloy

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Comments

Forseth11 · Accepted Answer · 2015-04-20 14:18:02Z

2

To exit a java program use:

System.exit(exit_code);

The exit code should be 0 if it is a normal exit and any other number means an abnormal termination. You can read more information about it here: https://docs.oracle.com/javase/7/docs/api/java/lang/System.html#exit(int)

answered Apr 20, 2015 at 14:18

Forseth11

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Jonas Czech · Accepted Answer · 2015-04-20 13:42:05Z

0

You should use System.exit(int StatusCode). This will exit your Java program with the specified exit code, eg. System.exit(0) will exit your program with status code 0.

From the docs:

Terminates the currently running Java Virtual Machine. The argument serves as a status code; by convention, a nonzero status code indicates abnormal termination.

answered Apr 20, 2015 at 13:42

Jonas Czech

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