use of init during inheritance in Python

Question

I am trying to build a simple HTTP server and am using BaseHTTPServer in python.

When ever I try to run the code below I get a error saying that init() takes exactly 4 arguments (1 given).

I guess the problem is that the constructor in handler is overriding the BaseHTTPServer.BaseHTTPRequest

Kindly let me know where I'm going wrong

class handler(BaseHTTPServer.BaseHTTPRequestHandler):
  def __init__(self,server):
    BaseHTTPServer.BaseHTTPRequestHandler.__init__(self)
    self.server = server
    self.port = 8080

def do_GET(self):
    #perform some operation
class server():

def __init__(self):
    self.port = 65531
    self.host = 'localhost'

def run(self):
    serverClass = BaseHTTPServer.HTTPServer
    server = "xyz.c1589.com"               # Some random server
    h = handler(server)
    server = serverClass((self.host,self.port),h)
    print "Starting server!!"
    try:
        server.serve_forever()
    except:
        print "Error Creating Server"
        server.server_close()


if __name__ == '__main__':
server().run()

BaseHTTPServer.BaseHTTPRequestHandler.__init__ takes three arguments and the subclass requires one, so when you instantiate a handler you need to pass four arguments. — wwii
– wwii, Commented Apr 18, 2015 at 2:04
When you are getting an error, you should post the complete traceback in your question. — wwii
– wwii, Commented Apr 18, 2015 at 2:06

Severin Pappadeux · Accepted Answer · 2015-04-18 01:56:31Z

1

The signature is BaseHTTPRequestHandler(request, client_address, server). Together with self it makes four arguments. You in __init__() provided only one

answered Apr 18, 2015 at 1:56

Severin Pappadeux

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Comments

L3viathan · Accepted Answer · 2017-11-22 10:38:05Z

0

BaseHTTPServer.BaseHTTPRequestHandler.__init__(self)

you need to put the args for the call to the base __init__ in there.

edited Nov 22, 2017 at 10:38

L3viathan

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answered Apr 18, 2015 at 1:56

Jules Gagnon-Marchand

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