swapping array indicy function with pointers

Question

After seeing this question Swapping in a char * array[ ] leading to issues

User Claudiu gave a solution to swap the position of a string in an array

 tmp = array[compare];
            array[compare] = array[index];
            array[index] = tmp;

However, i was wondering how to make that in a function by itself. using pointers, and I just can't understand the link between pointers and char arrays.

R Sahu · Accepted Answer · 2015-03-24 04:49:57Z

1

You can define a function:

void swapArrayItems(char* array[], int index1, int index2)
{
   char* tmp = array[index1];
   array[index1] = array[index2];
   array[index2] = tmp;
}

And then use it as:

swapArrayItems(array, compare, index);

answered Mar 24, 2015 at 4:49

R Sahu

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2 Comments

user3676224 Over a year ago

thank you very much, just one more tiny thing, what is the difference between having char* array[] and char *array in the argument?

R Sahu Over a year ago

char* array[] usually means an array of strings. char* array usually means an array of characters representing one string.

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