Parse JSON response in Android to access multidimensional array

Question

My json output is as follows:

How to parse it in Android?

I have been using iteration to loop over object collection1 without success. I want to access my array collection1 under object result:

if (jsonStr != null) {
    try {
        JSONObject jsonObj = new JSONObject(jsonStr);

        // Getting JSON Array node
        contacts = jsonObj.getJSONArray(TAG_CONTACTS);

        // looping through All Contacts
        for (int i = 0; i < contacts.length(); i++) {
            JSONObject c = contacts.getJSONObject(i);

            String id = c.getString(string1);
            String name = c.getString(string2);
            String email = c.getString(string3);
            String address = c.getString(string4);
            String gender = c.getString(string5);
            ...

Try to include more code, i.e. how do you get the jsonStr and at least complete the code snippet you included. — stefita
– stefita, Commented Mar 12, 2015 at 11:31

Ravi Shanker Yadav · Accepted Answer · 2015-03-12 11:44:18Z

1

This may help you:

if (jsonStr != null) {
  try {
       JSONObject jsonObj = new JSONObject(jsonStr);

       JSONObject jsonResult=jsonObj.getJSONObject("results");
   JSONArray jsonArrayCollection=jsonResult.getJSONArray("collection1");

       // looping through All Collection
       for (int i = 0; i < jsonArrayCollection.length(); i++) {
             JSONObject collctns = jsonArrayCollection.getJSONObject(i);
             String prop1Href=collctns.getJSONObject("property1").getString("href");
             String prop1Text=collctns.getJSONObject("property1").getString("text");
             String prop2=collctns..getString("property2")
      } 
  }catch(JSONException e){
     e.printStaceTrace();
  }
}

answered Mar 12, 2015 at 11:44

Ravi Shanker Yadav

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Comments

Gowtham Raj · Accepted Answer · 2015-03-12 11:10:52Z

0

Use Libraries Like GSON That will save u lot of time in parsing JSON data... here is a sample tutorial to get started..

Tutorial : link

answered Mar 12, 2015 at 11:10

Gowtham Raj

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