Regular Expression with python

Question

I have a tricky regular expression and I can't succeed to implement it.

I need the regular expression for this :

AEBE52E7-03EE-455A-B3C4-E57283966239

I use it for an identification like this :

url(r'^user/(?P<identification>\<regular expression>)$', 'view_add')

I tried some expressions like these ones:

\[A-Za-z0-9]{8}^-{1}[A-Za-z0-9]{4}^-{1}[A-Za-z0-9]{4}^-{1}[A-Za-z0-9]{4}^-{1}[A-Za-z0-9]{12}

\........^-....^-....^-....^-............

Someone can help me?

Thanks.

What are all those circumflexes for? They make it impossible for your regex to match anything. And what's with the backslash at the beginning? (On an other note; {1} is unnecessary.) — Biffen
– Biffen, Commented Mar 6, 2015 at 17:33

Avinash Raj · Accepted Answer · 2015-03-06 17:33:24Z

4

Just remove all the ^ symbols present in your regex.

>>> s = 'AEBE52E7-03EE-455A-B3C4-E57283966239'
>>> re.match(r'[A-Za-z0-9]{8}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{12}$', s)
<_sre.SRE_Match object; span=(0, 36), match='AEBE52E7-03EE-455A-B3C4-E57283966239'>
>>> re.match(r'[A-Za-z0-9]{8}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{12}$', s).group()
'AEBE52E7-03EE-455A-B3C4-E57283966239'

-{1} would be written as - It seems like all delimited words are hex codes. So you could use [0-9a-fA-F] instead of [A-Za-z0-9] .

>>> re.match(r'[0-9a-fA-F]{8}-[0-9a-fA-F]{4}-[0-9a-fA-F]{4}-[0-9a-fA-F]{4}-[0-9a-fA-F]{12}$', s).group()
'AEBE52E7-03EE-455A-B3C4-E57283966239'

answered Mar 6, 2015 at 17:33

Avinash Raj

175k32 gold badges247 silver badges289 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Lucas Trzesniewski Over a year ago

Same remark: [0-9a-fA-F] is more appropriate for GUIDs.

Kasravnd · Accepted Answer · 2015-03-06 17:46:26Z

1

You dont need ^ and for - dont need {1},you can use the following pattern :

\w{8}-\w{4}-\w{4}-\w{4}-\w{12}

Note that \w will match any word character (A-Za-z0-9)

Or :

\w{8}-(\w{4}-){3}\w{12}

And as mentioned in comment if you are using a UUID as a more efficient way you can use the following pattern :

[a-fA-F\d]{8}(-[a-fA-F\d]{4}){3}-[a-fA-F\d]{12}

DEMO

edited Mar 6, 2015 at 17:46

answered Mar 6, 2015 at 17:33

Kasravnd

108k19 gold badges167 silver badges195 bronze badges

3 Comments

Lucas Trzesniewski Over a year ago

Come on, that's a GUID... [0-9a-fA-F] is much more appropriate than \w.

Kasravnd Over a year ago

@LucasTrzesniewski where is A-F?

Kasravnd Over a year ago

@LucasTrzesniewski aha, yeah i miss that its UUID!

Collectives™ on Stack Overflow

Regular Expression with python

2 Answers 2

1 Comment

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related