Byte array to hex char array conversion [duplicate]

Question

My byte array is look like

 byte[] x = { (byte) 0xff , (byte) 0x80  };

how can i convert it to char array {char[] y } where:-

y[0]='f';
y[1] ='f' and so on

... and your "and so on" means what? Presumably you don't mean that every element in the array is 'f', which is what it looks like. — khelwood
– khelwood, Commented Mar 4, 2015 at 12:47
@Thilo Why did you marked this as duplicate? The Question is about convert to char array. Convert to string is not equal convert to char array in java. Especially when it concerns the passwords. — devops
– devops, Commented Nov 8, 2020 at 9:35

BeWu · Accepted Answer · 2015-03-04 12:53:35Z

11

This should help you:

byte[] data = { (byte) 0xff , (byte) 0x80  };
String text = new String(data, "UTF-8");
char[] chars = text.toCharArray();

edited Mar 4, 2015 at 12:53

answered Mar 4, 2015 at 12:48

BeWu

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5 Comments

Thilo Over a year ago

That doesn't yield { 'f', 'f', '8', '0' }

BeWu Over a year ago

Well that wasn't specified so i assumed he wants to convert the bytes into their corresponding character values...

Thilo Over a year ago

True. The question was clarified later.

Arjun Over a year ago

Thanks Thilo for the links, sharing code worked for me . byte[] x = {(byte) 0x80,(byte) 0x60}; StringBuilder sb = new StringBuilder(x.length * 2); for(byte b: x) sb.append(String.format("%02x", b & 0xff)); String s = sb.toString(); char[] array = s.toCharArray();

Dávid Horváth Over a year ago

This is unsafe for passwords.

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