Parsing JSON array and object in Android

Question

This is what the JSON looks like:

[{
    "pmid": "2",
    "name": " MANAGEMENT",
    "result": "1",
    "properties": [
        {
            "prop_id": "32",
            "prop_name": "Bonneville",
            "address": "122 Lakeshore",
            "city": "Ripley",
            "state": "OH",
            "zip": "11454",
            "lat": "41.123",
            "long": "-85.5034"
        }
    ]
}]

I am trying to parse it with the following Java code in Android:

JSONObject jObj = null; try { jObj = new JSONObject(jsonStr);

    // We get weather info (This is an array)
    JSONArray jArr = jObj.getJSONArray("properties");

    // We use only the first value
    //JSONObject JSONWeather = jArr.getJSONObject(0);
    JSONObject c = jArr.getJSONObject(0);
    String name = c.getString(TAG_NAME);
    String email = c.getString(TAG_EMAIL);
    String phone = c.getString(TAG_PHONE);
} catch (JSONException e) {
    e.printStackTrace();
}

return null;

I am not getting any results though. How can I successfully parse this JSON? I'm using Android Studio.

Also, if there were multiple pieces to the array, how could we make sure each one of them is printed out?

Niranj Patel · Accepted Answer · 2015-02-26 07:29:48Z

14

Your JSON string start with JSONArray.

Here sample code, try it.

    JSONArray mJsonArray = new JSONArray(jsonStr);
    JSONObject mJsonObject = mJsonArray.getJSONObject(0);

    String pmid = mJsonObject.getString("pmid");
    String name = mJsonObject.getString("name");
    String result = mJsonObject.getString("result");


    JSONArray mJsonArrayProperty = mJsonObject.getJSONArray("properties");
    for (int i = 0; i < mJsonArrayProperty.length(); i++) {
        JSONObject mJsonObjectProperty = mJsonArrayProperty.getJSONObject(i);

        String prop_id = mJsonObjectProperty.getString("prop_id");
        String prop_name = mJsonObjectProperty.getString("prop_name");
        String address = mJsonObjectProperty.getString("address");
        String city = mJsonObjectProperty.getString("city");
        String state = mJsonObjectProperty.getString("state");
        String zip = mJsonObjectProperty.getString("zip");
        String lat = mJsonObjectProperty.getString("lat");
        String lon = mJsonObjectProperty.getString("long");
    }

Check Android JSON Parsing Tutorial

edited Feb 26, 2015 at 7:29

answered Feb 26, 2015 at 7:14

Niranj Patel

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3 Comments

Adreamcathcer Adreamcatcher Over a year ago

This prints out one result, thank you for that. I am wondering, if it is not too much... how can I print all entries out, if there are multiple prop_id for example?

Niranj Patel Over a year ago

this is for loop so you can add all data in list

Adreamcathcer Adreamcatcher Over a year ago

Okay, what if the JSON was [{"pmid":"2","name":"MANAGEMENT","result":"1","properties":[{"prop_id":"32","prop_name":" Tower","address":"281 Lakeshore","city":"Euclid","state":"OH","zip":"44142","lat":"54.5","long":"-81.5034"}]},{"pmid":"1","name":"ONE","result":"18","properties":[{"prop_id":"3","prop_name":"Chase","address":"146 Goon Blvd.","city":"City","state":"OH","zip":"12345","lat":"46.35","long":"-83.1138"},{"prop_id":"6","prop_name":"Club Apartments","address":"4600 Barrington Club","city":"Columbus","state":"OH","zip":"43520","lat":"40.436","long":"-83.048"}]}]

ρяσѕρєя K · Accepted Answer · 2015-02-26 07:12:19Z

2

As in posted json String jsonStr is JSONArray of JSONObeject's instead of JOSNObject of JSONArray.

So convert jsonStr String to JSONArray:

JSONArray jArray = new JSONArray(jsonStr);
JSONObject c = jArray.getJSONObject(0);
// get properties JSONArray from c
 JSONArray jArrProperties = c.getJSONArray("properties");
 JSONObject jsonObject = jArrProperties.getJSONObject(0);

answered Feb 26, 2015 at 7:12

ρяσѕρєя K

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Comments

user4571931 · Accepted Answer · 2015-02-26 07:43:11Z

Here is complete example with resolution.

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;


public class Test {

public static void main(String[] args) 
{
     JSONObject jObj = null;
    try {
        String jsonStr = "[{\"pmid\":\"2\",\"name\":\" MANAGEMENT\",\"result\":\"1\",\"properties\":[{\"prop_id\":\"32\",\"prop_name\":\"Bonneville\",\"address\":\"122 Lakeshore\",\"city\":\"Ripley\",\"state\":\"OH\",\"zip\":\"11454\",\"lat\":\"41.123\",\"long\":\"-85.5034\"}]}]";
        jsonStr = jsonStr.substring(1, jsonStr.length()-1);
          System.out.println(jsonStr);
        jObj = new JSONObject(jsonStr);



        System.out.println("pmid="+jObj.get("pmid"));
        System.out.println("name="+jObj.get("name"));
        System.out.println("result="+jObj.get("result"));


        JSONArray jArr = jObj.getJSONArray("properties");

        JSONObject c = jArr.getJSONObject(0);

        System.out.println("prop_id=="+c.get("prop_id"));
        System.out.println("prop_name=="+c.get("prop_name"));
        System.out.println("address=="+c.get("address"));
        System.out.println("city=="+c.get("city"));
        System.out.println("state=="+c.get("state"));
        System.out.println("zip=="+c.get("zip"));
        System.out.println("lat=="+c.get("lat"));
        System.out.println("long=="+c.get("long"));


    } catch (JSONException e) 
    {
        e.printStackTrace();
    }
}

}

Midhun Mundayadan · Accepted Answer · 2015-02-26 07:14:21Z

in this exammple details object contain j son data

                  JSONObject details = mJSONParser.doInBackground(); //json object                
                  Child_Registration_StaticData deta=new Child_Registration_StaticData();
                    try
                    {
                        deta.UniqueID = details.getString("UniqueID");
                        deta.Nameofchild= details.getString("Nameofchild");
                        deta.FatherName= details.getString("FatherName");
                        deta.DOB= details.getString("DOB");

                        child_name.setText(deta.Nameofchild);
                        father_name.setText(deta.FatherName);
                        dateof_birth.setText(deta.FatherName);
                    }

Ravi K Thapliyal · Accepted Answer · 2015-02-26 07:14:40Z

0

Your root object is a JSON array [], not a JSON object {} there. So, you need

jObj = new JSONArray(jsonStr);
jObj = jObj.getJSONObject(0);

The rest of your code will now work fine treating jObj as a JSONObject. The concept here is exactly the same as what you're doing for your properties JSON array.

answered Feb 26, 2015 at 7:14

Ravi K Thapliyal

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Comments

iroiroys · Accepted Answer · 2015-02-26 07:33:19Z

0

use this

try {
            JSONArray array0 = new JSONArray(Sample);
            JSONObject object0 = array0.getJSONObject(0);
            JSONArray array1 = object0.getJSONArray("properties");
            JSONObject object1 = array1.getJSONObject(0);
            String name = object1.getString("prop_name");


        } catch (JSONException e) {
            e.printStackTrace();
        }

answered Feb 26, 2015 at 7:33

iroiroys

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